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3 years ago

Radii of congruent circles are equal. True False

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

8 0

Answer:

TRUE

Step-by-step explanation:

Two circles are congruent if they are equal in term of size. You can measure the size by comparing their diameter, radius or circumference. If two circles have the same radius, then they are said to be Congruent.

Therefore, the statement is TRUE ✅

Alla [95]3 years ago

5 0

true

I hope this helps you!

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RIGHT ANSWERS ONLY I REALLY NEED TO PASS IF YOUR FAST AND CORRECT ILL GIVE YOU BRAINEST!!!

malfutka [58]

Answer:

1st option

Step-by-step explanation:

The domain and range are all real numbers , that is

domain { x | x ∈ R }

range { y | y ∈ R }

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3 years ago

Solve the following inequality. 21<_-3(x - 4) < 30 A. 28<_x < 37 B. -3 <_ x < 6 C. -6 < x <_ -3 D. -10 &

Aloiza [94]

Answer:

Option C $-6$

Step-by-step explanation:

we have

$21\leq -3(x-4)$

The compound inequality can be divided into two inequality

$21\leq -3(x-4)$ -----> inequality A

$-3(x-4)$ ----> inequality B

Solve inequality A

$21\leq -3x+12$

$9\leq -3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$-3\geq x$

Rewrite

$x\leq -3$

The solution of the inequality A is the interval (-∞,-3]

Solve the inequality B

$-3x+12$

$-3x$

Divide by -3 both sides

when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$x>-6$

The solution of the inequality B is the interval [-6,∞)

The solution of the compound inequality is

[-6,∞) ∩ (-∞,-3]=(-6,-3]

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3 0

3 years ago

The expression 3(x-9) is equivalent to 3(x)+9 3(x)+3(9) 3(x)-9 3(x)-3(9)

ollegr [7]

3(x-9)

when you distribute the equation you get

3(x)-3(9) which is the last answer

6 0

3 years ago

Read 2 more answers

Ayudaaaaaaaaaaa por favor

Mazyrski [523]

Answer:

ayuda te solo no eres tonto o si?

Step-by-step explanation:

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3 years ago

Mauricio divided two identical rectangles into equal parts. He colored one part of each rectangle. What is true about the areas

Ivenika [448]

Answer:

Areas of the colored parts are equal

Step-by-step explanation:

Given Mauricio divided two identical rectangles into equal parts.

Now given Mauricio colored one part of each rectangle. we have to tell about the true statement of colored parts.

Two identical rectangles means the rectangle having equal areas. He divides these two into equal parts and shaded one of each part

Let area of rectangle is x $unit^{2}$

∴ Colored part area = $\frac{1}{2}xunit^{2}$ → (1)

Similarly, other rectangle area identical to above rectangle is x $unit^{2}$

∴ Colored part area = $\frac{1}{2}xunit^{2}$ → (2)

From above eq (1) and (2), we get

Areas of the colored parts are equal which is equals to $\frac{1}{2}xunit^{2}$

4 0

3 years ago