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lesantik [10]
2 years ago
5

Find the range Q1 and Q3 for the set of values, 36,36,48,65,75,82,92,101

Mathematics
1 answer:
Kaylis [27]2 years ago
3 0
The rang is based on values so maybe the range is 92
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ratio of a rectangle's length to its width is 4:7. If the longer side is 31.5in., find the width, the perimeter, and the area of
Nikitich [7]

Answer:

Step-by-step explanation:

Ratio of length : width = 4 : 7

Length = 4x

Width = 7x

Longer side = 31.5 in

⇒ 7x = 31.5

Divide both sides by 7

x = 31.5/7

x = 4.5

length = 4x

           = 4*4.5

         l = 18 in

width =  31.5

       w = 31.5 in

\boxed{ \text {Perimeter of  rectangle }= 2*l + 2*w}

                                      = 2*18 + 2*31.5

                                      = 36 +  63

                                      = 99 in

\boxed{ \text{Area of rectangle = l*w}}

                             = 18*31.5

                             =  567 in²

                             

3 0
1 year ago
What is the gcf of 5 (4x-3) +x (4x-3)? Explain
TiliK225 [7]
I more or less have an understanding, but,

Factor out the GCF of 4x-3 from 5(4x-3)+x(4x-3)

Making it,

(4x-3)(5+x)
7 0
2 years ago
ANSWER ASAP IS DUE IN 20 MINUITES (MIDDLE SCHOOL) (PROBABILITY)
lozanna [386]

Answer:

A ). 12

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which of these represents six miles less than twice the original distance?
Alexeev081 [22]
If the original distance is x, then twice the original distance is 2x.
6 less than something means minus six, or -6.
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7 0
2 years ago
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Write an equation of the parabola that opens up whose vertex (−1, 2) is 3 units from the focus. (Vertex form or Parabola Form is
TEA [102]

Answer:

y2  =  4ax (opens right, a > 0)

y2  =  -4ax (opens right, a > 0)

x2  =  4ay (opens up, a > 0)

x2  =  -4ay (opens down, a > 0)

Vertex at (h, k) :  

(y - k)2  =  4a(x - h) (opens right, a > 0)

(y - k)2  =  -4a(x - h) (opens right, a > 0)

(x - h)2  =  4a(y - k) (opens up, a > 0)

(x - h)2  =  -4a(y - k) (opens down, a > 0)

Equation of a Parabola in Vertex form

Vertex at Origin :  

y  =  ax2 (opens up, a > 0)

y  =  -ax2 (opens down, a > 0)

x  =  ay2 (opens right, a > 0)

x  =  -ay2 (opens left, a > 0)

Vertex at (h, k) :  

y  =  a(x - h)2 + k (opens up, a > 0)

y  =  -a(x - h)2 + k (opens down, a > 0)

x  =  a(y - k)2 + h (opens right, a > 0)

y  =  -a(y - k)2 + h (opens left, a > 0)

Step-by-step explanation:

7 0
2 years ago
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