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marshall27 [118]
3 years ago
14

Consumer Math Help?

Mathematics
2 answers:
labwork [276]3 years ago
8 0
I don't know if this would help but if your using a book you can find the answer at http://www.slader.com/subject/math/homework-help-and-answers/
rewona [7]3 years ago
4 0

Here we are given the equation:

y=10000*(0.97)^{x}

Here x represents the year.

Now plugging the value of x for different year :

A. x=1,

y=10000*(0.97)^{1}

y=9700

option A. 1 year is correct.

B. x=2,

y=10000*(0.97)^{2}

y=9404

But in the option we are given y=9308

So option B is incorrect.

C. x=3,

y=10000*(0.97)^{3}

y=9126.73

y= 9127 ( approx.)

So option C is correct.

D. x=4

y=10000*(0.97)^{4}

y=8852.9

y=8853 (approx)

So option D is also correct

Answer : option C. 3

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You may notice that all of the terms have a common factor: x. So, let's take the x out of all the terms. This gives us:

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Using the Zero Product Property, we can say that both x = 0 and x^2 + 2x - 24 = 0.

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Our answer is x = -6, 0, 4.


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