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3 years ago

In ▵ABC, if m∠A=80 degree, then m∠c cannot be

Mathematics

1 answer:

Aloiza [94]3 years ago

7 0

Answer:

Step-by-step explanation:

jdisusyhsyysysyydyydyyddhdhhdhhdhhd random

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Jake has a bag of 50 beads, some of which are blue and the remaining are green. Jake randomly pulls out a bead from the bag, rec

lana [24]

It should be D: 35. 14 + 6 = 20. I just multiplied that by two, which equals 40. That means there are 2 sets of 14 and 2 sets of 6. Since there is 10 leftover, I divided both by 2. 7 + 3 = 10. 14 x 2 = 28 + 7 = 35

3 0

3 years ago

Read 2 more answers

Hello, happy Friday, I am just here with some geometry questions.

klasskru [66]

Answer:

U'(-14, 8)

Step-by-step explanation:

<u>The transformations include:</u>

T<-2,2>·D3

This is a dilation by a scale factor of 3 and then translation 2 units left and 2 units up.

<u>The transformation applied to the point U:</u>

U(-4,2) → U'(-4*3 - 2, 2*3 + 2) = U'(-14, 8)

4 0

3 years ago

a sprinter running in the olympics starts at the 0 meter mark and ends at the 400 meter mark. it took him 65 seconds to run this

solniwko [45]

Answer:

I am not too sure but I think the answer would be 6

Step-by-step explanation:

3 0

2 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Help please! ill mark brainliest!

jenyasd209 [6]

Answer:

The answer is 90

Step-by-step explanation:

When HI=GH

Then m<G=m<I= 45

m<H=180-(45+45)=90

If you need any explanation in it or anything on math you can communicate with me on Whats on this number +201557831028 or in email or face or anything

4 0

2 years ago