Answer:
x= 5y−1 over 2
Step-by-step explanation:
Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
The gradient for a parallel line is the same.
perpendicular lines are negative reciprocals.
so all you have to do is re arrange it so y=Mx+b so the check out the gradients to what I listed above... remember y shouldn't have any number on it.
Answer:
3
Step-by-step explanation:
Answer:
None (If there are just these two options i.e, 249 and 50653. I think there are more options, anyway)
Step-by-step explanation:
Cubes of even numbers are even and cube of odd numbers are odd.
Since both the numbers are odd, both of their cubes must be odd too.
Thank You
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