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cricket20 [7]
3 years ago
15

-4x – 4y = -8 -2x + 4y = –10

Mathematics
1 answer:
shusha [124]3 years ago
8 0

Answer:

–10

Step-by-step explanation:

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Another sequence is defined by a term to term sequence where k and r are constants
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U(n + 1) = kU(n) + r

_________________________________

n = 1

U(1 + 1) = kU(1) + r

U(2) = k \times U(1) + r

188 = k \times (37) + r

37k + r = 188 \:  \: \:  (( \alpha ))_________________________________

n = 2

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U(3) = k \times U(2) + r

943 = k \times (188) + r

188k + r = 943 \:  \:  \: (( \beta ))

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188k  + r = 943 \:  \: \:  (( \beta ))

37k + r = 188 \:  \:  \: \:  \:  (( \alpha ))

(( \beta )) - (( \alpha )) =

188k - 37k + r - r = 943 - 188 \\

151k = 755

Divide sides by 151

\frac{151k}{151}  =  \frac{755}{151}  \\

k = 5

Put the value of k in one of the equations to find the r :

37k + r = 188

37 \times (5) + r = 188

185 + r = 188

r + 185 = 188

Subtract sides 185

r + 185 - 185 = 188 - 185

r = 3

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A Pew Research study finds that 23% of Americans use only a cell phone, and no land line, for making phone calls (The Wall Stree
azamat

Answer:

We accept H₀ sample does not give evidence to support that the proportion of Americans who solely use cell phone differs from 23 %

Step-by-step explanation:

A pew research finds  that  23 %  ( μ ) of Americans use only cell phone

Sample Information

sample size   n  = 200

x₁  =  51     then   p₁  = 51/200   p₁  =  0,255

and  q₁  =  1  - p ₁    q₁  =  1  - 0,255    q₁  =  0,745

Sample big enough for the approximation of the binomial distribution to the normal distribution

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Test hypothesis

Null hypothesis                       H₀              p₁  = μ = 0,23

Alternative hypothesis           Hₐ              p₁  ≠  0,23

Is a two tail test. We choose CI = 95 %  then significance level is                    α = 0,05 %

α = 0,05 as is a two tail test   α/2  = 0,025

from z-table  z(c) = 1,96

To calculate  z(s) = ( x  -  μ ) /√p₁*q₁/n  

  z(s) = ( 0,255 - 0,23 )/√0,255*0,745/200

z(s)  =  0,025 / 0,0308

z(s)  = 0,81

Comparing z(s)   and  z(c)

z(s) < z(c)      0,81 < 1,96

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