Answer: the first left equation is matching the description.
Step-by-step explanation
Since we know A= s2 ( exponent 2) and sis the side :
A=s2
A= 99sin2
s=square(99) sin
Answer:
1.504×10⁶ ft·lb
Step-by-step explanation:
We understand the top of the oil in the tank is 12 ft below ground level, and the bottom of the tank is 8+18=26 ft below ground level. Then the average depth of the oil is (12+26)/2 = 19 ft below ground level.
The height of the oil in the tank is 26-12=14 ft, so the volume of it is ...
V = πr²h = π(6 ft)²(14 ft) = 504π ft³ ≈ 1583.36 ft³
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So, the work required to raise that volume of oil to the surface is ...
(1538.36 ft³)(50 lb/ft³)(19 ft) = 1.504×10⁶ ft·lb
Answer:
A
Step-by-step explanation:
If you reflect figure P over the x-axis, it will be below the axis, below where figure P is. Then you need to move it 7 units right.
Answer: A
Answer:
Step-by-step explanation: