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Virty [35]
1 year ago
15

2. √2x-5-√x+6=0(solving the following radical equations and check for extraneous solutions)

Mathematics
1 answer:
Norma-Jean [14]1 year ago
5 0

I assume the equation is

√(2x - 5) - √(x + 6) = 0

Note the domains for the root expressions:

• √(2x - 5) : 2x - 5 ≥ 0   ⇒   x ≥ 5/2

• √(x + 6) : x + 6 ≥ 0   ⇒   x ≥ -6

So any valid solution we find must be at least 5/2.

Move one term to the other side.

√(2x - 5) = √(x + 6)

Take squares.

(√(2x - 5))² = (√(x + 6))²

2x - 5 = x + 6

Solve for x :

x = 11

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3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3​
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Given:

The equation is:

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

To find:

The value of a.

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We have,

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

On simplification, we get

(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}

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On comparing both sides, we get

6-12a=-18

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8-3a=2

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There are 6 marbles in a bag. are blue and 2 are red. What is the probability of
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yaroslaw [1]

Answer:

m∠RQS = 72°

m∠TQS = 83°

Step-by-step explanation:

m∠RQS +m ∠TQS = m∠RQT

The two angles combine to make a larger angle

So

m∠RQS = (4x - 20)

m∠TQS = (3x + 14)

(4x - 20) + (3x + 14) = 155

Group the Xs and the constants

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Combine like terms

7x - 6 = 155

Add 6 to both sides

7x = 161

Divide by 7 on both sides

x = 23

Check:

4(23) - 20 + 3(23) + 14 = 155

92 - 20 + 69 + 14 = 155

155 = 155

But we need to find m∠RQS and m∠TQS. So plug in x = 23 to the values.

m∠RQS = 4(23) - 20 = 72°

m∠TQS = 3(23) + 14 = 83°

Checking:

72 + 83 = 155

8 0
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The diameter of a sphere with a volume of 12,348 cubic ft is ___ ft.
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Answer:

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