There are three boys and three girls at a party. in how many ways can they be seated in a row if they must sit alternating boys
1 answer:
The number of permutations of the three girls is 3P3 = 6. Similarly the number of permutations of the boys is 6. Each permutation of girls can be taken with each permutation of boys. Additionally each arrangement from left to righr can have a girl first or a boy first.
Total number of ways is given by:
Total number of ways is given by:
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Option A
The new price is $
Given that, a stock was priced at $ per share.
It rose in price by $ per share.
New price = old price + rise in price
Thus to find out the new price, we have to add old price and rise in price
On solving we get,
On converting to mixed fraction,
Hence, the new price is , so option A is correct.