There are three boys and three girls at a party. in how many ways can they be seated in a row if they must sit alternating boys
1 answer:
The number of permutations of the three girls is 3P3 = 6. Similarly the number of permutations of the boys is 6. Each permutation of girls can be taken with each permutation of boys. Additionally each arrangement from left to righr can have a girl first or a boy first.
Total number of ways is given by:
Total number of ways is given by:
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Answer:
49
Step-by-step explanation:
Given:
Width = 0.4
Let's take the z value of 95% which is = 1.96
Let's assume population proportion p1 and p2 = 0.5
For margin of error E, the relation between the width and margin of error is 2E.
i.e 2E = 0.4
E = 0.2
To find the sample size, n, let's use the formula :
= 48.02
≈ 49