The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=
the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)
btw nCr=n!/(n-r)!r!
good luck
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
Answer:
-4 and 4
Step-by-step explanation:
Have a good day.
Answer: I think the answer is D
Step-by-step explanation:
Answer:
I took the test!!
Step-by-step explanation:
Pit this in your calculator exactly like this 4,000(1.05)^5 and you get the answer 5,105.12625. So round your answer to the nearest dollar, which is 5,105.