The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
18×30%=
18×.30=5.4
5.4 is the amount of clearanceyou get from the item
Know you have to subtract $5.40 from $18.00
18-5.4=12.6
The item is know $12.60
Line b and h because to find radius it half of the diameter of STRAIGHT lines
Answer:
i tried but i dont understand sorry
Step-by-step explanation:
