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2 years ago

Question 9 (5 points)

Mathematics

1 answer:

Ad libitum [116K]2 years ago

3 0

9514 1404 393

Answer:

$3291.60

Step-by-step explanation:

If the loan is amortized in the usual way, the monthly payment is ...

A = P(r/12)/(1 -(1 +r/12)^(-12t)) . . . . . loan of P at rate r for t years

A = $15,000(0.081/12)/(1 -(1 +0.081/12)^(-12·5)) ≈ $304.86

The total of payments is ...

(60 months) × ($304.86/month) = $18,291.60

Then the profit to the bank is ...

$18,291.60 -15,000 = $3,291.60 . . . bank profit

You might be interested in

Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

5 0

3 years ago

Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200

-Dominant- [34]

Answer:

1348 light years.

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.

$(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)$

Upon substituting our given values in above formula we will get,

$x^2=1200^2+1700^2-2*1200*1700*cos (52^o)$

$x^2=1440000+2890000-4080000*0.615661475$

$x^2=4330000-2511898.81933008$

$x^2=1818101.18066992$

Let us take square root of both sides of our equation.

$x=\sqrt{1818101.18066992}$

$x=1348.3698234\approx 1348$

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0

2 years ago

I NEED HELP ON DOING THIS

stira [4]

If all the angles add up to 90 degrees then you can set the equation 7x-9*2x=90
Simplify
9x-9=90
Plus 9 both sides
9x=99
Divide by 9 on both sides
X=11

4 0

2 years ago

Read 2 more answers

Sam bought six new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There are n

victus00 [196]

Answer:70

Step-by-step explanation:

multiply 38 to get 76 and then subtract 6

4 0

3 years ago

Read 2 more answers

Pauline is building a fence around her vegetable garden, what length of fence will she need to build?

Nuetrik [128]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
First we look for the hypotenuse of both triangles.
Left triangle:
Sine (68.1) = (1.75) / (h)
h = (1.75) / Sine (68.1)
h = 1.886108667
h = 1.9m
Right triangle:
Sine (49.4) = (1.75) / (h)
h = (1.75) / Sine (49.4)
h = 2.304841475
h = 2.3m
Finally adding the perimeter:
P = 5 + 1.9 + 2.75 + 2.3
P = 11.95 m
Answer:
she will need to build 11.95 m of fence

6 0

3 years ago