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Law Incorporation [45]
2 years ago
10

Question 9 (5 points)

Mathematics
1 answer:
Ad libitum [116K]2 years ago
3 0

9514 1404 393

Answer:

  $3291.60

Step-by-step explanation:

If the loan is amortized in the usual way, the monthly payment is ...

  A = P(r/12)/(1 -(1 +r/12)^(-12t)) . . . . . loan of P at rate r for t years

  A = $15,000(0.081/12)/(1 -(1 +0.081/12)^(-12·5)) ≈ $304.86

The total of payments is ...

  (60 months) × ($304.86/month) = $18,291.60

Then the profit to the bank is ...

  $18,291.60 -15,000 = $3,291.60 . . . bank profit

You might be interested in
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
3 years ago
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
2 years ago
I NEED HELP ON DOING THIS
stira [4]
If all the angles add up to 90 degrees then you can set the equation 7x-9*2x=90
Simplify
9x-9=90
Plus 9 both sides
9x=99
Divide by 9 on both sides
X=11
4 0
2 years ago
Read 2 more answers
Sam bought six new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There are n
victus00 [196]

Answer:70

Step-by-step explanation:

multiply 38 to get 76 and then subtract 6

4 0
3 years ago
Read 2 more answers
Pauline is building a fence around her vegetable garden, what length of fence will she need to build?
Nuetrik [128]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 SEE ATTACHED IMAGE. 
 First we look for the hypotenuse of both triangles.
 Left triangle:
 Sine (68.1) = (1.75) / (h)
 h = (1.75) / Sine (68.1)
 h = 1.886108667
 h = 1.9m
 Right triangle:
 Sine (49.4) = (1.75) / (h)
 h = (1.75) / Sine (49.4)
 h = 2.304841475
 h = 2.3m
 Finally adding the perimeter:
 P = 5 + 1.9 + 2.75 + 2.3
 P = 11.95 m
 Answer: 
 she will need to build 11.95 m of fence

6 0
3 years ago
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