ANSWER

EXPLANATION
Part a)
Eliminating the parameter:
The parametric equation is


From the first equation we make t the subject to get;


We put it into the second equation.


We differentiate to get;

At x=5,


The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by




Without eliminating the parameter,



At x=5,



This implies that,

The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by



Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
If all the angles add up to 90 degrees then you can set the equation 7x-9*2x=90
Simplify
9x-9=90
Plus 9 both sides
9x=99
Divide by 9 on both sides
X=11
Answer:70
Step-by-step explanation:
multiply 38 to get 76 and then subtract 6
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
First we look for the hypotenuse of both triangles.
Left triangle:
Sine (68.1) = (1.75) / (h)
h = (1.75) / Sine (68.1)
h = 1.886108667
h = 1.9m
Right triangle:
Sine (49.4) = (1.75) / (h)
h = (1.75) / Sine (49.4)
h = 2.304841475
h = 2.3m
Finally adding the perimeter:
P = 5 + 1.9 + 2.75 + 2.3
P = 11.95 m
Answer:
she will need to build 11.95 m of fence