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Marina CMI [18]

4 years ago

14

Someone help please ...!

1 answer:

jenyasd209 [6]4 years ago

6 0

The missing angle number is 75
43+62=105
180-105=75

and it looks like a acute angle less than

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Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3,

lakkis [162]

Answer:

(1, 1)

Step-by-step explanation:

Given vertices of the <u>parallelogram</u>:

H = (-1, 4)
J = (3, 3)
K = (3, -2)
L = (-1, -1)

Therefore the <u>parallel sides</u> are:

$\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}$

Therefore, the <u>diagonals</u> of the parallelogram are:

$\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}$

To find the <u>coordinates of the intersection of the diagonals</u>, either:

draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, or
determine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).

<u>Midpoint between two points</u>

$\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)$

To find the <u>midpoint of diagonal LJ</u>, define the endpoints:

$(x_1,y_1)=L=(-1, -1)$
$(x_2,y_2)=J=(3,3)$

Substitute the defined endpoints into the formula and solve:

$\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}$

Therefore, the coordinates off the intersection of the diagonals of parallelogram HJKL are (1, 1).

Learn more about midpoints here:

brainly.com/question/27962681

8 0

2 years ago

Read 2 more answers

Is this relation a function? (PLEASE ANSWER!) last time i was ignored

ANTONII [103]

No it is not, because the value 3 in the domain is repeating, therefore it is not a function

3 0

3 years ago

The expression 1/2mv^2<br> M=1.6x10^3<br> V=3.4x10^3

mariarad [96]

Answer:

Step-by-step explanation:

hello :

The expression 1/2mv^2

M=1.6x10^3

V=3.4x10^3

is : 1/2(1.6x10^3 )(3.4x10^3)²=2.72x 10^9

8 0

4 years ago

100 points PLEASE ANSWER ASAP thank you so much

Fudgin [204]

Answer:

$\textsf{Apply the Perfect Square Formula}\quad (a + b)^2 = a^2 + 2ab + b^2:$

$\implies (a+bi)^2=a^2+2abi+(bi)^2$

$\textsf{Apply exponent rule} \quad (a\cdot b)^c=a^cb^c:$

$\implies a^2+2abi+b^2i^2$

$i=\sqrt{-1} \implies i^2=-1$

$\textsf{Apply imaginary number rule} \quad i^2=-1:$

$\implies a^2+2abi+b^2(-1)$

$\implies a^2+2abi-b^2$

$\textsf{Collect the real parts:}$

$\implies a^2-b^2+2abi$

$\textsf{Factor the real parts by applying the Difference of Two Squares Formula}\\x^2-y^2=(x+y)(x-y) :$

$\implies (a+b)(a-b)+2abi$

4 0

2 years ago

Read 2 more answers

Cynthia Besch wants to buy a rug for a room that is 20 ft wide and 26 ft long. She wants to leave a uniform strip of floor aroun

Radda [10]

Answer:

16 ft by 22 ft

Step-by-step explanation:

The Area of the carpeting she must have = 352 ft²

To solve for this, we have:

Length × Width = Area of a rectangle

352ft² = Length × Width

352ft² = (20 - x) (26 - x)

352 = 520 - 20x - 26x + x²

352 = 520 - 46x + x²

Collect like terms

x² - 46x + 520 - 352

x² - 46x + 168

We factorise

x² - 4x - 42x + 106

(x² - 4x) -(42x + 106)

x(x - 4) -42(x - 4)

(x - 4)(x - 42)

x - 4 = 0, x = 4

x - 42 = 0, x = 42

We choose the least value for x

Hence, x = 4

Length = 20 - 4 = 16ft

Width = 22- 4= 22ft

The dimensions the rug should have is 16ft by 22 ft, meaning 16ft wide and 22ft long

4 0

3 years ago