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Maru [420]
2 years ago
14

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
Amanda [17]2 years ago
7 0

The number of comic books is an illustration of a linear function

  • The complete equations are: \mathbf{8b + 17 =65} and \mathbf{b =6}
  • The value of b has increased by 4

She had 17 comic books already.

So, we have:

\mathbf{Base\ Amount = 17}

Her order of 65 books contains 8 comic books per collection.

So, we have:

\mathbf{Rate = 8}

\mathbf{Total = 65}

This is represented as:

\mathbf{Rate \times b + Base\ Amount =Total}

So, we have:

\mathbf{8\times b + 17 =65}

Rewrite as:

\mathbf{8b + 17 =65}

Subtract 17 from both sides

\mathbf{8b =48}

Divide both sides by 8

\mathbf{b =6}

Assume she has 97 books in her collection, then the equation would be represented as:

\mathbf{8b + 17 = 97}

Subtract 17 from both sides

\mathbf{8b  = 80}

Divide both sides by 8

\mathbf{b  = 10}

The values of b are 6 and 10.

The difference between 6 and 10 is 4

Hence, the value of b has increased by 4

Read more about linear equations at:

brainly.com/question/11897796

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4a x 6a⁵ ÷ 8a²<br><br>please answer the question in full steps, thank you ​
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Answer:

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3 years ago
Read 2 more answers
Mya told her friend, “If you increase my sisters age by 6, multiply that quantity by 12, and then subtract 4, you get 10. Write
Lostsunrise [7]

Answer: x+6(12-4) = 10

Step-by-step explanation:

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3 years ago
PLEASE HELP ME!! (50 COINS) (i rlly need help so im giving coins away PLEASE ANSWER IMMEDIATELY!!!)
Archy [21]

Hello from MrBillDoesMath!

Answer:

4( x + 1.5)^2 + 0  

Discussion:

4x^2 + 12x + 9 =                => factor "4" from first 2 terms

4 (x^2 + 3x) + 9 =               => complete the square, add\subtract (1.5)^2

4(x^2 + 3x + (1.5)^2)  - 4 (1.5)^2 + 9  =

4 ( x + 1.5)^2 + ( 9 - 4(1.5)^2) =           => as (1.5)^2 = 2.25

4 ( x + 1.5)^2 + ( 9 - 4(2.25)) =        => as 4 ( 2.25) = 9

4 ( x+ 1.5)^2 + 0


Thank you,

MrB

5 0
3 years ago
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