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slega [8]
3 years ago
7

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

<h2>y=<u> -2</u>x+<u>7</u></h2>

<u>Here</u><u>,</u>

Two points given: (3,1) and (7,-7)

slope(m) =  \frac{y2 - y1}{x2 - x1}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{ - 7 - 1}{7 - 3}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{ - 8}{4}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  - 2 \\

Equation of line is y= Mx+b

y= -2x +b

It passes through (3,1)

1 =  - 2(3) + b \\ 1 =  - 6 + b \\  - b =  - 6 - 1 \\  - b =  - 7 \\ b = 7

Equation of line:

<h3>y= -2x+7</h3>

Hope this helps..

Good luck on your assignment..

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The surface area of a cylinder is increasing at a rate of 9 pi square meters per hour. The height of the cylinder is fixed at 3
Alekssandra [29.7K]

Answer:

9\pi \text{ cubic meters per hour}

Step-by-step explanation:

Since, the surface area of a cylinder,

A= 2\pi r^2 + 2\pi rh  ................(1)

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h = height,

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18 = r^2 + 3r

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r^2 + 6r - 3r - 18 = 0     ( by middle term splitting )

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By zero product property,

r = 3 or r = - 6 ( not possible )

Thus, radius, r = 3 meters,

Now, differentiating equation (1) with respect to t ( time ),

\frac{dA}{dt}= 4\pi r\frac{dr}{dt} +2\pi(r\frac{dh}{dt} + h\frac{dr}{dt})

∵ h = constant, ⇒ dh/dt = 0,

\frac{dA}{dt} = 4\pi r \frac{dr}{dt} +2\pi h \frac{dr}{dt}

We have, \frac{dA}{dt}=9\pi\text{ square meters per hour}, r = h = 3\text{ meters}

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9\pi = (12\pi + 6\pi )\frac{dr}{dt}

9\pi = 18\pi \frac{dr}{dt}

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Now,

Volume of a cylinder,

V=\pi r^2 h

Differentiating w. r. t. t,

\frac{dV}{dt}=\pi ( r^2 \frac{dh}{dt}+h(2r)\frac{dr}{dt})=\pi ((3)(6) (\frac{1}{2})) = 9\pi \text{ cubic meters per hour}

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Answer:

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Step-by-step explanation:

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