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77julia77 [94]
3 years ago
12

In a statistics mid-term exam graded out of 100 points, the distribution of the exam scores was bi-modal with a mean of 70 point

s with a standard deviation of 10 points. What percentage of students scored between 40 points and 100 points?
Mathematics
2 answers:
MrRissso [65]3 years ago
5 0

Step-by-step explanation:

At least 89%

.............................

ur welcome

Mnenie [13.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

Assuming a normal distribution for the distribution of the points scored by students in the exam, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean score

s = standard deviation

From the information given,

u = 70 points

s = 10.

We want to find the probability of students scored between 40 points and 100 points. It is expressed as

P(40 lesser than x lesser than or equal to 100)

For x = 40,

z = (40 - 70)/10 =-3.0

Looking at the normal distribution table, the corresponding z score is 0.0135

For x = 100,

z = (100 - 70)/10 =3.0

Looking at the normal distribution table, the corresponding z score is 0.99865

P(40 lesser than x lesser than or equal to 100) = 0.99865 - 0.0135 = 0.98515

The percentage of students scored between 40 points and 100 points will be 0.986 × 100 = 98.4%

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B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

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<span>possible choices.</span><span> 
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