A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
285 liters is 75.289 U.S. gallons.
The answer is A
Step-by-step explanation:
The solution and explanation is pinned
Answer: 0.12
Step-by-step explanation:
The expected number of accidents is a weighted average of the potential number of accidents and their probabilities:
= (0 * 0.935) + (1 * 0.03) + (2 * 0.02) + (3 * 0.01) + (4 * 0.005)
= 0.12
A linear function that includes the points you gave would be:
f(x)=3x+10
OR
y=3x+10
I hope this helps!