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nikdorinn [45]
3 years ago
9

What is a decomposition reaction?

Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

11-6√3 = a -b√3

where a=11 and b =6

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given

      \frac{5+2\sqrt{3} }{7+4\sqrt{3} }

Rationalize

=    \frac{5+2\sqrt{3} }{7+4\sqrt{3} } X \frac{7-4\sqrt{3} }{7-4\sqrt{3} }

=    \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{7^{2} -(4\sqrt{3})^{2}  }

=  \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{49-16(3)  }

= \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{1  }

<u><em>Step(ii):-</em></u>

<em>Multiply</em>

<em>     </em>{(5+2\sqrt{3})(7-4\sqrt{3} ) }

=  5 × 7 - 5×4√3 + 2√3 ×7 - 2√3 × 4√3

= 35 -20√3+ 14√3-8×3

= 35 - 6√3 -24

= 11-6√3

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A red candle is 8 inches tall and burns at a rate of 7/10 inch per hour. A blue cans is 6 inches tall and burns at a rate of 1/5
Mazyrski [523]

Answer:

It would take 4 hours for both candles to be the same height

Step-by-step explanation:

Total time (t) for red candle to be same height (h) can be expressed as;

Final height after time t=Initial height-rate per hour

where;

Final height after time=h

Initial height=8 inches

Rate per hour=rate×time=(7/10)×t=0.7t

Substituting;

h=8-0.7t

Total time (t) for blue candle to be same height (h1) can be expressed as;

Final height after time t=Initial height-rate per hour

where;

Final height after time=h1

Initial height=6 inches

Rate per hour=rate×time=(1/5)×t=0.2t

Substituting;

h1=6-0.2t

Since h=h1

8-0.7t=6-0.2t

8-6=0.7t-0.2t

0.5t=2

t=2/0.5

t=4 hours

It would take 4 hours for both candles to be the same height

6 0
4 years ago
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kolezko [41]
F(1) is the first term of the arithmetic sequence, then f(1)=-9

Common difference: 7
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5-(-2)=5+2=7
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Answer: Fourth option
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