There is one zero in the ten thousands place.
There is another zero in the hundreds place.
Both of them have the value of zero.
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
7 because 7•3=21 and if he has as twice much as you 7•2=14 & 14+7=21 books together
Answer:
B
Step-by-step explanation:
Use the given functions to set up and simplify f(-3x)
substitute x with -3x
-2 (-3x) =6x remember a - x - = +
6x +5
