Question

What is the vertex of the quadratic equation below? y=x^2-8x+1 Explanation?

Answer 1

To find the vertex, you need to find the axis of symmetry first.

In order to find the axis of symmetry we have to do -b/2a.

In our case, the b is -8 and the a is 1.

Plug it in.

-(-8)/2(1)

8/2 = 4

Our axis of symmetry is 4.

Now, we plug it into the equation to find the rest of the vertex.

y = 4^2 - 8(4) + 1

y = 16 - 32 + 1

y = -16 + 1

y = -15

Put it together.

Our vertex is (4,-15).