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raketka [301]
3 years ago
6

What is the vertex of the quadratic equation below? y=x^2-8x+1 Explanation?

Mathematics
1 answer:
scoray [572]3 years ago
3 0

To find the vertex, you need to find the axis of symmetry first.

In order to find the axis of symmetry we have to do -b/2a.

In our case, the b is -8 and the a is 1.

Plug it in.

-(-8)/2(1)

8/2 = 4

Our axis of symmetry is 4.

Now, we plug it into the equation to find the rest of the vertex.

y = 4^2 - 8(4) + 1

y = 16 - 32 + 1

y = -16 + 1

y = -15

Put it together.

Our vertex is (4,-15).

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The answer is:  "4" .
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<u>Note</u>:  The question asks for a whole number.

"The area of the triangle above will equal one half of a rectangle that is 5 units long and <u>  4  </u><u /> units wide.  (Input only whole numbers, such as 8.).
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<u>Note</u>:  The diagram shows a "right triangle" ; which would be "one-half" of a rectangle, with units of "length" being "5 units" (as mentioned in this very question prompt;  and a width of "4" units (as shown in the diagram;  hence the answer is "4" units). 

Furthermore, the formula/equation for the area, "A" , of a triangle is: 


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Area = (1/2) * (base length) * (perpendicular height).
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As such, the answer, "4" (units) makes sense.
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The value of the expression when g = -2 is -1

<h3>How to simplify the expression</h3>

Given the expression;

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brainly.com/question/4344214

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