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Advocard [28]
3 years ago
5

Match the element with their place on the periodic table.

Chemistry
1 answer:
Doss [256]3 years ago
4 0

Answer:

Period 4, group 5- Vanadium

Period 5, group 7- Technetium

Period 7, group 5- Dubnium

Period 5, group 4- Zirconium

Explanation:

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Explanation:

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What is this reaction CaSO4--> CaO+SO3
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The reaction where one component splits into two or more is a decomposition reaction.
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What is the total concentration of an acetic acid solution (ch3cooh) with a ph of 3.5? acetic acid ka = 1.76 x 10-5 m?
marin [14]

The dissociation reaction of acetic acid is as follows:

CH_{3}COOH\leftrightharpoons CH_{3}COO^{-}+H^{+}

The acid dissociation constant K_{a} is 1.76\times 10^{-5}.

Let the initial concentration of acid be A, and concentration of CH_{3}COO^{-} and H^{+} be zero.

After dissociation, concentration of acid becomes A-x and that of both CH_{3}COO^{-} and H^{+} becomes x.

Expression for acid dissociation constant will be:

K_{a}=\frac{[CH_{3}COO^{-}][H^{+}]}{[CH_{3}COOH]}

pH of solution is 3.5, thus, concentration of hydrogen ion can be calculated as follows:

pH=-log[H^{+}]

On rearranging,

[H^{+}]=10^{-pH}=10^{-3.5}=0.0003162

Since, [CH_{3}COO^{-}]=[H^{+}]=x

Thus,

[CH_{3}COO^{-}]=0.0003162

and, x=0.0003162

Putting the values, in expression for acid dissociation constant,

1.76\times 10^{-5}=\frac{(0.0003162)(0.0003162)}{[CH_{3}COOH]_{initial}-0.0003162}

On rearranging,

[CH_{3}COOH]_{initial}=\frac{(0.0003162)\times (0.0003162)}{1.76\times 10^{-5}}+0.0003162=0.006

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n = c / v  

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