Answer: B) Ten moles of sodium hydroxide and five moles of hydrogen gas will be produced
Explanation: Got it right on USATestPrep
The Answer is A Building Blocks
Answer:
363.64g of oxygen would be required.
Explanation:
1) Write and balance the combustion equation for propane.
Propane + Oxygen --> carbon dioxide + water
C3H8 + O2 --> CO2 + H2O
Upon balancing, we have;
C3H8 + 5O2 --> 3CO2 + 4H2O
2) How many grams of oxygen are required to burn 200 grams of propane.
From the reaction;
Propane = (3 * 12) + (8 * 1) = 44
Oxygen = (5 * 16) = 80
80 grams of oxygen is required to combust 44g of propane.
80 = 44
x = 200
x = ( 80 * 200 ) / 44
x = 363.64g
9.56Moles Chromium X 6.022X10^23 Atoms Divide by 1moles of Chromium = 5.76X10^24 atoms of Chromium
.we can read the chemical preparation of the reaction as: "4 g of hydrogen react with 32 g of oxygen to give 36 g of water". :)
