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MrRissso [65]
1 year ago
9

PLEASE HELP DUE IN 15!!!!!!!!!!!! WILL GIVE BRAINLIEST!!

Chemistry
1 answer:
maria [59]1 year ago
4 0

Explanation:

n=,4.5 moles C2H6

the ratio 2:7

4.5:x

x=15.75 moles

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How many moles in 3.69 x 10^30 molecules of carbon dioxide?
elixir [45]

Answer:

four million two hundred and thirty

Explanation:

7 0
3 years ago
Can I get some help?
Brut [27]
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6 0
3 years ago
Predict the boiling point of water at a pressure of 1.5 atm.
Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

ln\frac{P_{1} }{P_{2}} =-Δ\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}}  )

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the
Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

V_2 = \frac{P_1P_2}{P_2}  that is V₂ = \frac{1atm*1.32L}{90atm} = \frac{11}{750}L or 0.01467L

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!! Determine the volume of a container that holds 2.4 mol of gas at STP.
kykrilka [37]

Answer:

2.4 mol x 22.4 liter = 53.76 liters

1 mole

Explanation:

5 0
3 years ago
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