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4 years ago

How much heat is required to heat a 5.0 g pyrex glass dish (c=0.176 J/gC) from 23 degrees C to 65 degrees C?

Chemistry

1 answer:

swat324 years ago

3 0

Answer:

Q = 36.96 j

Explanation:

Given data:

Mass of pyrex glass dish = 5.0 g

Specific heat capacity = 0.176 j/g.°C

Initial temperature = 23 °C

Final temperature = 65°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 65°C - 23 °C

ΔT = 42°C

Q = 5 g× 0.176 j/g.°c ×42°C

Q = 36.96 j

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Which is an example of chemical weathering?

kobusy [5.1K]

Answer:

b. the layer of oxide formed on statues made of metal

Explanation:

Chemical weathering is a process whereby rocks are disintegrated or weathered causing a chemical reaction thereby leading to change in the parent rock constituents .

In chemical weathering a new substance is usually formed after the weathering takes place.

From the question the layer of statue made by metal will likely form oxides of those metals. Example Silver will react with oxygen to form an entirely new substance like silver(i)oxide.

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3 years ago

Lithium hydroxide is used in alkaline batteries. Calculate the molarity of a solution prepared by dissolving 1.495 moles of LiOH

weeeeeb [17]

Answer:1)1.99 M

Explanation:

Molarity is given as = moles solute/Liter solution

The solute which is LiOH is already given in moles as 1.495 moles

Given that solution is 750 mL, we convert to liters.

Liters of the solution= mL of the solution x (1 L/1000 mL)

750 mL x (1 L/1000 mL)

0.75 L

Molarity = moles solute/Liter solution

Molarity = 1.495 moles of LiOH/0.75 L of solution

Molarity = 1.99M

The molarity of this solution is 1.99M (moles per liter).

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3 years ago

Where glucose is broken down into smaller molecules to produce energy. The second part of the process takes place in the

slavikrds [6]

Answer:

Mitochondria

Explanation:

Glucose in an energy molecule contained in carbohydrate food substances. The end product of the digestion of carbohydrate is glucose which is broken down to produce energy.

The sequence of breakdown of glucose is as follows; In the first step, 6-carbon glucose is broken down into two molecules of 3-carbon pyruvic acid. This occurs in the cytoplasm of the cell. It is an anaerobic process.

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3 years ago

Write an equation that shows why aspirin gives an acidic solution when dissolved in water.

dolphi86 [110]

Answer:

Do you still need this answer? :)

Explanation:

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4 years ago

Consider a simple reaction in which a reactant AA forms products: A→productsA→products What is the rate law if the reaction is z

levacccp [35]

Answer :

The rate law expression for zero order reaction will be:

$Rate=k[A]^0$

The rate law expression for first order reaction will be:

$Rate=k[A]^1$

The rate law expression for second order reaction will be:

$Rate=k[A]^2$

Zero order reaction : There is no affect on the rate law.

First order reaction : The rate law becomes doubled.

Second order reaction : The rate law becomes quadrupled.

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The given reaction is:

$A\rightarrow Products$

The rate law expression for zero order reaction will be:

$Rate=k[A]^0$

The rate law expression for first order reaction will be:

$Rate=k[A]^1$

The rate law expression for second order reaction will be:

$Rate=k[A]^2$

Now we have to determine that if doubling of the concentration of A then the rate of reaction will be:

As we know that the zero order reaction does not depend on the concentration of reactant. So, there is no affect on the rate law.

As we know that the first order reaction depend on the concentration of reactant. So, the rate law becomes doubled.

As we know that the second order reaction depend on the concentration of reactant. So, the rate law becomes quadrupled.

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4 years ago