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galina1969 [7]
3 years ago
10

What is 2-3+2.4*7.690+23.145+ square root 25 

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0
45.601 is the answer.
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What is 1/9 x 4/5? please help
Anni [7]

Answer:

4/45

Step-by-step explanation:

Multiply the top by the top, and the bottom by the bottom:

\frac{1}{9} * \frac{4}{5} = \frac{4}{45}

4/45 cannot be reduced down anymore, therefore that is your answer.

<em>Hope this helps!!</em>

<em>- Kay :)</em>

8 0
3 years ago
Read 2 more answers
What are the measures of Angles a, b, and c? Show your work and explain your answers.<br> 25 points
bogdanovich [222]

Answer:

a=40

b=50

c= 115

Step-by-step explanation:

The first angle we will find is angle c

65 and angle c make a straight line so they add to 180

c+65 = 180

Subtract 65 from each side

c+65 -65 =180-65

c = 115


Angle a and 40 are vertical angles

Vertical angles are equal

angle a = 40


The sum of the angles in a triangle are equal to 180

a+b+ right angle = 180

40+ b + 90 = 180

130 +b = 180

Subtract 130 from each side

130-130+b = 180-130

b= 50

5 0
4 years ago
What step is incorrect
tatyana61 [14]

Answer:

3

Have a great day!!

5 0
2 years ago
Read 2 more answers
When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in i
Westkost [7]

Answer:

(1) 256 inches

(2) 5 feet

(3) 400 inches

(4) 10 feet

Step-by-step explanation:

(1) The function that gives the height in inches of the spray of water at a distance <em>x</em> from the sprinkler head is given as follows;

h(x) = 160·x - 16·x²

At x = 2 feet, we have;

h(2) = 160 × 2 - 16 × 2² = 256

Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches

(2) The x-coordinate, x_{max}, of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;

x_{max} = -b/(2·a)

The x-coordinate, x_{max}, of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;

x_{max} = -160/(2 × (-16)) = 5

Therefore, the number of feet along the way, the function will reach maximum height, x_{max} = 5 feet

(3) The function, h(x) = 160·x - 16·x², will reach maximum height, h_{max}, at x = 5, therefore;

h_{max} =  h(5) = 160 × 5 - 16 × 5² = 400

The maximum height of the spray, h_{max} = 400 inches

(4) The water is at ground level where h(x) = 0, therefore;

At ground level, h(x) = 0 = 160·x - 16·x²

160·x - 16·x² = 0

∴ 16·x × (10 - x) = 0

By zero product rule, we 16·x = 0, or (10 - x)  = 0, from which we have;

x = 0, or x = 10

The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.

7 0
3 years ago
A table of values of a linear function is shown below. Find the output when the input is n
Colt1911 [192]
Could you insert a photo of the linear function?
6 0
2 years ago
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