Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
----------------
Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
5a
Step-by-step explanation:
Solution
verified
Verified by Toppr
We have x
3
−ax
2
+6x−a
Apply remainder theorem
x−a=0
x=a
Put x=a in equation.
(a)
3
−a(a)
2
+6a−a
=a
3
−a
3
+6a−a
=6a−a
=5a
Then reminder is 5a
Answer:
b=7
Step-by-step explanation:
3-5b=-32
-5b=-32-3
-5b=-35
Divide both sides by -5
b=7
