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Neko [114]
2 years ago
10

After completing a fraction division problem, Clarice used multiplication to check her answer.

Mathematics
1 answer:
Taya2010 [7]2 years ago
8 0

Answer:

Step-by-step explanation:

After completing a fraction division problem, Clarice used multiplication to check her answer. Division: 7 and one-half divided by 1 and one-half = 5. Check: 5 times 1 and one-half = 5 and one-half. Could Clarice verify her answer? Explain.After completing a fraction division problem, Clarice used multiplication to check her answer. Division: 7 and one-half divided by 1 and one-half = 5. Check: 5 times 1 and one-half = 5 and one-half. Could Clarice verify her answer? Explain.Why can you use fraction multiplication to check the answer to a fraction division problem? How do you use multiplication to check a division problem?

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\left \{ {{4x+6y=8} \atop {5x-4y=25}} \right. \\ \left \{ {{4x+6y=8} \atop {5x=25+4y}} \right.\\ \left \{ {{4x+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{4(5+0.8y)+6y=8} \atop {x=5+0.8y }} \right. \\  \left \{ {{20+3.2y+6y=8} \atop {x=5+0.8y }} \right. \\ \left \{ {{9.2y=-12} \atop {x=5+0.8y }} \right. \\ \left \{ {{y= -\frac{12}{9.2} } \atop {x=5+0.8y }} \right. \\  \left \{ {{y= -\frac{120}{92} } \atop {x=5+0.8(-\frac{12}{9.2}) }} \right. \\
\left \{ {{y= -1\frac{28}{92} } \atop {x=5-\frac{96}{92} }} \right. \\  \left \{ {{y= -1\frac{7}{23} } \atop {x=5-1\frac{1}{23} }} \right. \\   \left \{ {{y= -1\frac{7}{23} } \atop {x=4\frac{1}{23} }} \right. \\
\boxed{(x; y)=(4\frac{1}{23}; -1\frac{7}{23}) }





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