Solve your system of equations.
2x+y=1;4x+2y=−1
Solve 2x+y=1 for y:
2x+y+−2x=1+−2x(Add -2x to both sides)
y=−2x+1
Substitute (−2x+1) for y in 4x+2y=−1:
4x+2y=−1
4x+2(−2x+1)=−1
2=−1(Simplify both sides of the equation)
2+−2=−1+−2(Add -2 to both sides)
0=−3
Answer: No solution. C)
Answer:
Step-by-step explanation:
First, let's look at the largest triangle (two smaller triangles are combined) to solve for 
. Since the sum of the angles in a triangle adds up to 
, we can write the equation:
Looking at the smaller triangle on the left, 
(exterior angle) is the sum of the two opposite interior angles of the triangle on the left:
Since 
is the exterior angle of the triangle on the right, it is equivalent to the sum of the opposite interior angles of that triangle:
Hope this helps :)
10/100=0.1
1/4=0.25
0.1*0.25=0.025
To get the distance DC we proceed as follows:
AB-CD
=11-3
=8
BC=15
hence using Pythagorean theorem
c²=a²+b²
c=DC
a=BC
b=8
thus
c²=15²+8²
c²=225+64
c²=289
thus
c=√289
c=17 units
Answer: B. 17 units
