Answer:
∠ A ≅ ∠ E
∠ K = 60°
Step-by-step explanation:
Part 1.
Given that ABCD ≅ EFGH.
Whenever a quadrilateral is congruent to another, and we write the congruency in symbol, then the order of congruency with respect to angles and sides are maintained in the symbol.
That means if ABCD ≅ EFGH, then ∠ A ≅ ∠ E, ∠ B ≅ ∠ F and so on.
Therefore, in this case, ∠ A ≅ ∠ E (Answer) {It is also shown in the diagrams}
Part 2.
Given that, Δ EFG ≅ Δ KLM
Hence, ∠ E ≅ ∠K, ∠ F ≅ ∠ L, and ∠ G ≅ ∠ M
It is also given that ∠ F = 35° and ∠ G = 85°
So, ∠ E = 180° - ∠ F - ∠ G = 180° - 85° - 35° = 60°
Since, ∠ E = ∠ K,
So, ∠ K = 60°. (Answer)
Answer:
(4,-6)
Step-by-step explanation:
I graphed it.
Ps, https://www.geogebra.org/graphing is very good for graphing equations and such if you have the equations formated correcly.
Much luck to you!
It's b. Group all the pounds together and all the volumes together. Small packages weigh 30 lbs (30x), lg pkgs weight 65 lbs (65y) and together they weigh at most 3800 lbs. So 30x + 65y <= 3800 (they divided each of those terms by 5 to get 6x + 13y <= 760). Next take the volumes: small pkgs have a volume of 4 ft^3 (4x) and lg pkgs have a volume of 9 ft^3 (9y) and together they are no more than 400 ft^3. So 4x + 9y <= 400. It's b.
- Correct. This is the distance around the circle, aka the perimeter.
- False. Going from center (O) to the point A is the radius, which is half the diameter. Answer: radius
- Correct. The diameter is a chord that goes through the center. A chord is any segment where the endpoints are on the circle's edge.
- Correct. There are three radii shown in this diagram. The other radius is OC. Segment BC is a chord that is neither a diameter nor a radius.
In short, all you need to do is change "diameter" to "radius" in question 2. Other than that, you're perfect.