Y=6/X; X= 9 what is the answer and how do you solve this?

FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli

____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0

1 year ago

Using a number cube and this hat with 5 different-colored marbles, which simulation would help you answer this question? During

Arlecino [84]

Answer:

see the attachment

Step-by-step explanation:

We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).

Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.

That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".

The simulation of 70 different choices of a random class is shown in the attachment.

_____

Comment on the question

IMO, the use of 70 trials is coincidentally the same number as the first 70 days of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.

5 0

3 years ago

A student concludes that the solution to the equation ( 2×+1+3=0 is×=4

Slav-nsk [51]

Answer:

x = -2

Step-by-step explanation:

2x + 1 + 3 = 0

2x + 4 = 0

x = -2

4 0

3 years ago

2cosx-3=0 cách giải như thế nào

Masteriza [31]

Answer:

Solution does not exist.

Step-by-step explanation:

2cosx-3=0

2cosx=3

cosx=3/2

Solution does not exist.

7 0

3 years ago

Find the m∠CDE, if m∠BAC = 50° and ∠BCA is a right angle. 40° 50° 90° 180°

serious [3.7K]

< BAC = 50
< BCA = 90

interior angles of a triangle add up to 180

so < ABC = 180 - (90 + 50) = 180 - 140 = 40

and < ABC = < CDE.......so < CDE = 40 <===

6 0

3 years ago

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