<u>Solution</u><u>:</u>


- Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

- Now, transpose 4x and 4 to LHS.

- Now, do the addition and subtraction.

<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>
Hope you could understand.
If you have any query, feel free to ask.
Option C:
![$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Solution:
Given expression is
![$\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Note: ![\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D%5Csqrt%5B3%5D%7B%7B5%5E3%7D%7D%20%20%3D%205)
To find the correct expression for the above simplified expression.
Option A: ![\frac{\sqrt[3]{4 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B5%7D)
5 can be written as
.
![$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B4%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{4x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4x%7D%7B125%7D%20%7D)
It is not the given simplified expression.
Option B: ![\frac{\sqrt[3]{20 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B5%7D)
![$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B20%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{20x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B20x%7D%7B125%7D%20%7D)
Cancel the common factor in both numerator and denominator.
![$=\sqrt[3]{\frac{4x}{25} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4x%7D%7B25%7D%20%7D)
It is not the given simplified expression.
Option C: ![\frac{\sqrt[3]{100 x}}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D)
![$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B%5Csqrt%5B3%5D%7B125%7D%20%7D)
![$=\sqrt[3]{\frac{100x}{125} }](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B100x%7D%7B125%7D%20%7D)
Cancel the common factor in both numerator and denominator.
![$=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
It is the given simplified expression.
Option D: ![\frac{\sqrt[3]{100 x}}{125}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B125%7D)
![$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B125%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%5E3%7D)
It is not the given simplified expression.
Hence Option C is the correct answer.
![$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}](https://tex.z-dn.net/?f=%24%5Cfrac%7B%5Csqrt%5B3%5D%7B100%20x%7D%7D%7B5%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B4%20x%7D%7B5%7D%7D)
Answer:
Point Y (4, -1) lies on the circle.
Step-by-step explanation:
Distance = √[(x2-x1)² + (y2 - y1)²] = √[(4-1)² + (-1-(-5))²] = √[3² + 4²]= √25 = 5
Point Y (4, -1) lies on the circle, because the distance from the center to this point equals radius of the circle.
Answer:
a) 1 / 10
b) $15/10 = $1.50
Step-by-step explanation: