Question

Can someone plz help me Thank you in advance:)

Answer 1

Answer : The specific heat of the metal is, $2178.67J/kg^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of ice = $2000J/kg^oC$

$m_1$ = mass of metal = 1.00 kg

$m_2$ = mass of ice = 1.00 kg

$T_f$ = final temperature of mixture = $-8.88^oC$

$T_1$ = initial temperature of metal = $5.00^oC$

$T_2$ = initial temperature of ice = $-24.0^oC$

Now put all the given values in the above formula, we get:

$(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]$

$c_1=2178.67J/kg^oC$

Therefore, the specific heat of the metal is, $2178.67J/kg^oC$