Complete Question
A company uses paper cups shaped like cones for its water cooler. Each cup has a height of 10 cm, and the base has a diameter of 12 cm. The cooler has 16,956 cm³ of water in it. How many cups can be filled from the cooler?
Answer:
45 paper cups
Step-by-step explanation:
Step 1
We have to find the volume of the paper cups.
The paper cup is shaped like a cone
Hence, Volume of a cone(paper cup) = 1/3πr²h
π = 3.14
Height = 10 cm
Diameter = 12 cm
Radius = Diameter/2 = 12cm/2 = 6cm
Hence,
Volume = 1/3 × 3.14 × 6² × 10
= 376.8 cm³
Step 2
How many cups can be filled from the cooler?
The cooler contains initially = 16,956 cm³ of water
Hence, the number of cups that can be filled from the cooler is calculated as:
Volume of cooler/Volume of paper cup
= 16,956cm³/376.8 cm³
= 45 paper cups
Therefore, 45 paper cups can be filled from the cooler.
Answer: part a: area = bh part b: split it on its diagonals
Step-by-step explanation:
Answer:
C.)
| 7 | = | -7|
Step-by-step explanation:
because absolute values are always positive....so, absolute values of | -7 | and | 7 | are both 7
Answer:
1) The square ABCD was dilated to form square A'B'C'D' using a scale factor of 1/2
2) The pair of polygons is not similar because their corresponding sides are not proportionals.
Step-by-step explanation:
1) Scale factor: f=?
f=Final dimension / Initial dimension
f=A'B'/AB=B'C'/BC=C'D'/CD=A'D'/AD
f=2/4
Simplifying the fraction dividing the numerator and denominator by 2:
f= (2/2) / (4/2)
f=1/2
2) Let's check the proportion between their corresponding sides:
AM/A'M'=(11 ft)/(9.4 ft)=1.17
HT/H'T'=(11 ft)/(9.4 ft)=1.17
HM/H'M'=(10 ft)/(8.4 ft)=1.19
AT/A'T'=(10 ft)/(8.4 ft)=1.19
AM/A'M'=HT/H'T'=1.17 but different to 1.19=HM/H'M'=AT/A'T'
Then, the pair of polygons is not similar
Answer:
3
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
9/3 = 3
The common ratio is 3