Question:
A sample of cans of peaches was taken from a warehouse, and the content of each can mearsed for weight. the sample means was 486g with stand deviation 6g. state the weight percentage of cans with weight:
Draw normal curve to help - split into 8 section ( i can't draw it here)
a) 34.13% of cans will be between 480g and 486g.
b) 13.59 + 2.15 + 0.13= 15.87% of cans greater than 492g.
Look at the Stand Dev Graph where the give you the number
Step-by-step explanation:
Let me give you a different question and i will answer it, which you help you answer your question.
9 × 13<em>ˣ</em> = 9 × exp(ln(13<em>ˣ </em>))
… = 9 × exp(<em>x</em> ln(13))
… = <em>A</em>₀ × exp(<em>kx</em>)
so that
<em>A</em>₀ = 9
<em>k</em> = ln(13)
What's the rest of the question?
