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3 years ago

Use the horizontal ruler to measure the horizontal distance between two crests. what is this distance?

1 answer:

8 0

It seems some part of the text is missing, however, since we are talking about 'crests' I guess we are talking about waves.

In a wave, the distance between two consecutive crests corresponds to the wavelength of the wave. Therefore, the distance measured with the ruler is the wavelength of the wave.

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Determine which of the following relations is a function.

fomenos

Answer:

The farthest left box.

Step-by-step explanation:

In order for a relation to be a function, the order of numbers must be constant from the input to the output. The other numbers do not have a consistent value, but the one on the far left is x=+5 and y=-5, and it continues this way throughout the relation.

Hopefully this helped!

6 0

4 years ago

Read 2 more answers

I NEED HELP ASAP PLEASE<3

Paul [167]

lDK

but friend me on discord, and follow my robIox account, then we will talk.

discord: datboythomas123#8606

robIox: chexmix1202

4 0

3 years ago

Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.