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Makovka662 [10]
4 years ago
5

Which are true regarding the statement “A quadrilateral having exactly one pair of parallel opposite sides USA trapezoid”?Check

all that apply.
Mathematics
1 answer:
Mashcka [7]4 years ago
4 0

Answer:

A). It is a conditional statement that can be written as “If a quadrilateral has exactly one pair of parallel opposite sides, then it is a trapezoid."

B). The hypothesis is: a quadrilateral having exactly one pair of parallel opposite sides.

E). The conclusion is: it is a trapezoid.

Step-by-step explanation:

I just did the assignment on Edge. It's 100% correct!!  Hope this helps!!

Also heart and rate if you found this answer helpful.

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Alexxx [7]

Answer:

No, they are not scaled copy's.

Step-by-step explanation:

So we can flip figure F to where it is facing the direction that figure A is.

First we do 105 divided by 35, the corresponding sides, and get 3. If you do 96 divide by 19, you get 5.052631579. You are free to use my explanation word for word as your reason why.    

6 0
3 years ago
If angle 1 and angle 2 are supplementary angles, and angle 3 and angle 2 are supplementary angles, what do you know about angle
dusya [7]

Answer:

  angle 1 and angle 3 are congruent

Step-by-step explanation:

Angles supplementary to the same angle are congruent. Here both angles 1 and 3 are supplementary to angle 2, so angles 1 and 3 are congruent.

_____

If you like, you can get there algebraically:

  m∠1 + m∠2 = 180

  m∠3 + m∠2 = 180

Subtract the second equation from the first:

  (m∠1 + m∠2) - (m∠3 + m∠2) = (180) - (180)

  m∠1 -m∠3 = 0 . . . . simplify

  m∠1 = m∠3 . . . . . . add m∠3

When angle measures are the same, the angles are congruent.

  ∠1 ≅ ∠3

4 0
4 years ago
Can someone help me with this test?
iogann1982 [59]

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Step-by-step explanation:

6 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3?
crimeas [40]

Answer:

\large\boxed{x=-2-\sqrt{\dfrac{11}{2}}\ \text{and}\ x=-2+\sqrt{\dfrac{11}{2}}}

Step-by-step explanation:

f(x)=2x^2+8x-3\\\\\text{You can use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{We have}\ a=2,\ b=8,\ c=-3\\\\\text{Substitute:}\\\\b^2-4ac=8^2-4(2)(-3)=64+24=88\\\\\sqrt{b^2-4ac}=\sqrt{88}=\sqrt{4\cdot22}=\sqrt4\cdot\sqrt{22}=2\sqrt{22}\\\\x=\dfrac{-8\pm2\sqrt{22}}{2(2)}=\dfrac{-8}{4}\pm\dfrac{2\sqrt{22}}{4}=-2\pm\dfrac{\sqrt{22}}{2}=-2\pm\dfrac{\sqrt{22}}{\sqrt4}\\\\x=-2\pm\sqrt{\dfrac{22}{4}}=-2\pm\sqrt{\dfrac{11}{2}}

5 0
3 years ago
Read 2 more answers
Parallelogram ABCD is a rectangle.
svp [43]
Y = 3 because in a rectangle, the diagonals are ALWAYS congruent. so you would have:
5y - 2 = 4y + 1
-4y+2   -4y + 2
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7 0
4 years ago
Read 2 more answers
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