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Citrus2011 [14]
4 years ago
10

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

end of one year he earned $112 in interest. How much money was invested in each account? Which of the following equations could be used to solve the problem?
A) 0.02x + 0.04(800) = 112
B) 0.02x + 0.04(x + 800) = 112
C) 0.04x + 0.02(x + 800) = 112
Mathematics
2 answers:
rodikova [14]4 years ago
5 0
The correct answer is B
If you let x = amount invested at 2% (which is 0.02), then x + 800 = amount invested at 4% (which is 0.04).

Masteriza [31]4 years ago
4 0

The answer should be B or the second choice.

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Answer:A)

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Step-by-step explanation:

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As y=12000x hence the relationship is proportional.

B)

We calculate the equation of the graph with the help of two points on the graph namely (2,24000) and (4,48000) with the help of slope-intercept form of the line.

y=mx+c where m denotes the slope of the line and c denotes the y-intercept of the line.

Here when x=2 y=24000 and when x=4 y=48000

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Step-by-step explanation:

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2 years ago
What’s variance and how do I figure it oit
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<h2>Answer:</h2>

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masya89 [10]

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Quantity sold by Emil at lunchtime = Quarter of what was left = (1/4)(x/2) liters = x/8 liters, that is the one-eight fraction of x.

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Learn more about fractions at

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<span>The probability that one customer will place a take-out order is .45.
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