A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

Question

Citrus2011 [14]

4 years ago

10

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the

end of one year he earned $112 in interest. How much money was invested in each account? Which of the following equations could be used to solve the problem?
A) 0.02x + 0.04(800) = 112
B) 0.02x + 0.04(x + 800) = 112
C) 0.04x + 0.02(x + 800) = 112

Mathematics

2 answers:

rodikova [14] · Answer 1 · 2021-11-20T08:49:13+03:00

rodikova [14]4 years ago

5 0

The correct answer is B
If you let x = amount invested at 2% (which is 0.02), then x + 800 = amount invested at 4% (which is 0.04).

Masteriza [31] · Answer 2 · 2021-11-20T10:01:10+03:00

Masteriza [31]4 years ago

4 0

The answer should be B or the second choice.