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3 years ago

14

Six students measure the acceleration (in meters per second per second) of object in free fall. The measured values are shown. T

he students want to state that the absolute deviation of each measured value x from the mean is at most d. Find the value of d. 10.56, 9.52, 9.73, 9.80, 9.78, 10.91

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

The measured data is
x=[10.56, 9.52, 9.73, 9.80, 9.78, 10.91].

Calculate the mean.
m = (10.56+9.52+9.73+9.80+9.78+10.91)/6 = 10.05

Calculate the deviations from the mean.
k = x - m
= [0.51, -0.53, -0.32, -0.25, -0.27, 0.86]

Calculate the absolute deviation from the mean.
$d= \frac{1}{6} | (0.51-0.53-0.32-0.25-0.27+0.86) | = |1.184\times10^{-15}| \approx 0$

Answer: 0

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