All categories

3 years ago

3.What is the center of the circle?

Mathematics

1 answer:

Sophie [7]3 years ago

8 0

Answer:

it's (3,-1) and this has to be 20 characters so yeah

You might be interested in

F(x)=x2. what is g(x)?

Leto [7]

Answer:

Step-by-step explanation:

Hi again. In this case, the graph enlarges. Coefficient of x is <1. Try to substitute x = 3 to (1/3x)^2 and (1/9x^2)

(1/3 * (3))^2=1

5 0

3 years ago

What is 2 3/4 as a decimal?

Vesna [10]

Answer:

2.75

Step-by-step explanation:

first convert it to a improper fraction

2 3/4 = 11/4

then dividing the numerator by the denominator.

11/4 = 2.75

hope this helped!

5 0

3 years ago

Read 2 more answers

A normal distribution has a mean of 80.6 and a standard deviation of 13.9. Find the value where the lowest 5% of data ends.

Akimi4 [234]

Answer:

The lowest 5% of data ends at 57.73.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with mean μ = 80.6 and standard deviation σ = 13.9.

The lowest 5% of the distribution can be expressed in terms of probability as follows:

$P(X$

Compute the value of x as follows:

$P(\frac{X-\mu}{\sigma}$

The z score such that P (Z < z) = 0.05 is z = -1.645.

**Use the z-table for the for the z-score.

The value of x is:

$z=\frac{x-\mu}{\sigma} \\-1.645=\frac{x-80.6}{13.9} \\x=80.6-(1.645\times13.9)\\=57.7345\\\approx57.73$

Thus, the lowest 5% of data ends at 57.73.

7 0

3 years ago

96 is 44 percent of what? Step by step

Elena-2011 [213]

Answer:

$218.18$

Step-by-step explanation:

To find what number 96 is 44% of is we can use the formula:

$\frac{part}{whole} =\frac{percent}{100}$

Just substitute 94 and 44 into the equation:

$\frac{96}{x} =\frac{44}{100}$

$9600=44x\\218.1818...$

Or rounded,

$218.18$

4 0

3 years ago

Q4 Help pleaseeeeeeee

emmasim [6.3K]

a. The general equation for a circle centered at $(a,b)$ with radius $r$ is

$(x-a)^2+(y-b)^2=r^2$

The described circle has equation

$(x+3)^2+(y+2)^2=r^2$

We know the circle passes through the origin. This means that the equation above holds for $x=0$ and $y=0$ . The distance between any point on the circle and its center is the radius, so we can use this fact to determine $r$ :

$(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}$

So the circle's equation is

$(x+3)^2+(y+2)^2=(\sqrt{13})^2=13$

b. If the distance between point B and the center is less than $\sqrt{13}$ , then B lies inside the circle. If the distance is greater than $\sqrt{13}$ , it falls outside the circle. Otherwise, if the distance is exactly $\sqrt{13}$ , then B lies on the circle.

The distance from B to the center is

$\sqrt{(-1+3)^2+(3+2)^2}=\sqrt{4+25}=\sqrt{29}$

$29>13$ , so $\sqrt{29}>\sqrt{13}$ , which means B falls outside the circle.

5 0

3 years ago