Question

find two consecutive odd integers such as that 6 times the lesser integer is 7 more than 5 times the greater integer​

Answer 1

Answer:

The first consecutive integer is 17 while the second is 19

Step-by-step explanation:

Let us say that the first odd integer is x

At this point, the second odd integer will be x+2.

This is because to obtain the next consecutive odd integer, 2 will have to be added to the original number.

From the question, we can set up an equation as shown below:

$6x= 7+5(x+2)$

from this, we can simply evaluate and find out the value of x

$6x=7 +5x +10\\x=17$

therefore, the first consecutive integer is 17 while the second is 19