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tatuchka [14]
4 years ago
10

find two consecutive odd integers such as that 6 times the lesser integer is 7 more than 5 times the greater integer​

Mathematics
1 answer:
aivan3 [116]4 years ago
3 0

Answer:

The first consecutive integer is 17 while the second is 19

Step-by-step explanation:

Let us say that the first odd integer is x

At this point, the second odd integer will be x+2.

This is because to obtain the next consecutive odd integer, 2 will have to be added to the original number.

From the question, we can set up an equation as shown below:

6x= 7+5(x+2)

from this, we can simply evaluate and find out the value of x

6x=7 +5x +10\\x=17

therefore, the first consecutive integer is 17 while the second is 19

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The equation of the line that is parallel<br> to 4x+2 and passing through (5,15)
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Answer:

y=4x-5.

Step-by-step explanation:

slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;

1) to find value of k:

if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;

2) to find the value of 'b':

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3 years ago
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irina1246 [14]
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(When simplifying fractions, you should <em>never</em> have a square root on the bottom. Multiply by the square root to cancel it out)
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4 years ago
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Answer:

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The dog will run the 21-mile race in 4.04 hours

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