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3 years ago

VERY MUCH HELP VERY PLEASE

1 answer:

3 0

1) 5/9 divided by 3/5
2) flip 3/5 to 5/3
3) multiply 5/9 and 5/3
4) it equals 25/27

.....I think this is how you do it?

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I need help asap someone please help me i dont understand this question so can someone help me

eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

7 0

3 years ago

8,20,50... what are the next terms? find the 6th term.

natulia [17]

I can answer this but I need more terms

8 0

3 years ago

The absolute value function, f(x) = |x + 2|, is shown. If the graph is reflected over the x-axis, what is the domain of the func

inna [77]

Answer:

Step-by-step explanation:

given f(x)=|x+2 |

after reflection f'(x)=-|x+2|

domain is same.

domain is all real numbers.

5 0

3 years ago

−3 1/3÷1.2= write it as a mixed number i simplest form

GenaCL600 [577]

Answer:

I got -2.7

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

Which of the following is a monomial A. 5x^2+2x+3 B. √x-1 C. 4x D. 3/x

earnstyle [38]

C. 4x

Have a good day ;)

7 0

3 years ago