w trójkącie równoramiennym abc podstawa AB ma długość 10cm. Odcinek AD jest wysokością tego trójkąta. Wiedząć że |DB|=6cm,oblicz
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Answer:
Vertex → (2, 4)
Step-by-step explanation:
Quadratic equation has been given as,
y = -x² + 4x
We rewrite this equation in the form of a function as,
f(x) = - x² + 4x
By comparing this equation with the standard quadratic equation,
y = ax² + bx + c
a = -1 and b = 4
Vertex of the parabola represented by this equation is given by
x coordinate =
= 2
y-coordinate = f(2)
= - (2)² + 4(2)
= -4 + 8
= 4
Therefore, vertex of the given function is (2, 4)