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erik
[133]
3 years ago
10
w trójkącie równoramiennym abc podstawa AB ma długość 10cm. Odcinek AD jest wysokością tego trójkąta. Wiedząć że |DB|=6cm,oblicz
obwód trójkąta.
Mathematics
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2
answers:
Alik
[6]
3 years ago
5
0
Translate to English for help
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Olegator
[25]
3 years ago
3
0
I cannot solve this because it's written in a foreign language that i don't understand. I am very sorry I wish I could help.
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