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erik [133]
3 years ago
10

w trójkącie równoramiennym abc podstawa AB ma długość 10cm. Odcinek AD jest wysokością tego trójkąta. Wiedząć że |DB|=6cm,oblicz

obwód trójkąta.
Mathematics
2 answers:
Alik [6]3 years ago
5 0
Translate to English for help
Olegator [25]3 years ago
3 0
I cannot solve this because it's written in a foreign language that i don't understand. I am very sorry I wish I could help.
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