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3 years ago

10

w trójkącie równoramiennym abc podstawa AB ma długość 10cm. Odcinek AD jest wysokością tego trójkąta. Wiedząć że |DB|=6cm,oblicz

obwód trójkąta.

2 answers:

Alik [6]3 years ago

5 0

Translate to English for help

Olegator [25]3 years ago

3 0

I cannot solve this because it's written in a foreign language that i don't understand. I am very sorry I wish I could help.

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3 years ago

Solve.<br> y=x - 7<br> 5+2y=7

lesantik [10]

Answer:

$\huge\boxed{x=8;\ y=1\to(8;\ 1)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=x-7&(1)\\5+2y=7&(2)\end{array}\right\\\\\text{Substitute (1) to (2) and solve for x:}\\\\5+2(x-7)=7\qquad\text{use the distributive property}\\\\5+(2)(x)+(2)(-7)=7\\\\5+2x-14=7\\\\2x+(5-14)=7\\\\2x-9=7\qquad\text{add 9 to both sides}\\\\2x-9+9=7+9\\\\2x=16\qquad\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{16}{2}\\\\\boxed{x=8}$

$\text{Substitute it to (1):}\\\\y=8-7\\\\\boxed{y=1}$

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DochEvi [55]

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