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uysha [10]
3 years ago
15

I need help with number #11

Mathematics
1 answer:
nikklg [1K]3 years ago
4 0

Answer:

KJFJDSKLJDKLFJDSKJDSFKDMF;DS MDF NM FDSF DS FSDFSD FJJKFSDN DSF DSJFJDSFDNFDFNDMFDNSAFJASNF,MASFNAS2`1849 ,MNFNMADBFASBJ2L31U93O2KQN 4Y72 7IW4N LOOK THIS UP TO GET ANSWERS

Step-by-step explanation:

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i know the answer to be "B" because we just learned this in class


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Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0
Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

therefore

The roots of the equation are x=-3 and x=-2.5

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Answer:

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200 - 130 = 70

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