
Factor the polynomial.
2(
)
2(x-2)
Factor the other Polynomial.
3


This is your answer.

The answer is A to the question
A Yes as the x values are all different
B f(x) = 5x + 14
when x = 2 , f(x) = 5(2) + 14 = 24
x = 5, f(x) = 39,
Each value of f(x) is greater than corresponding ones in the function in A.
when x = 9 f(x) = 59 which is greater than for first function ( =12)
First function is a decreasing while f(x) is increasing
C f(x) = 64 = 5x + 14
5x = 64 - 14 = 50
x = 10
Answer:
20/3 or 6.67 or 6
(any of these are correct)
Step-by-step explanation:
Volume of triangular pyramid formula is V = 1/3 * base area * height
V = 1/3 * 5 * 4 = 20/3
20/3 or 6.67 or 6 
Calculate area of the white region inside circle.
Area of the two white triangles in top left and bottom right:

Area of the two white quarter circles in the bottom left and top right:

Total area of unshaded white region inside circle:

Area of entire circle including the white and shaded regions

Area of shaded region is area of entire circle - area of unshaded white region
