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Alex73 [517]
3 years ago
6

After you complete your survey of students reported heights at your school, you discover that your sample is biased. Exactly 10%

of the students in your sample tended to over report their height more than the average student in the general population at the school. What conclusion can you reach about the mean of the average difference in your sample?
Mathematics
2 answers:
RSB [31]3 years ago
5 0

Answer:

The mean of the reported heights at the school is 0.75 greater than the the mean of the actual measured heights at the school.

Readme [11.4K]3 years ago
3 0
What we can say with a good deal of certainty is that our sample is biased towards the higher spectrum and that the real value of the mean for our population is lower than the obtained value of our sample. If this is true, we should expect for the standard deviation to be higher than in the population. 
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schepotkina [342]

The area of the triangle ABC is 207.5 square units.

Explanation:

The measurements of the sides of the triangle are AB=19, AC=24 and m\angle A=65^{\circ}

We need to determine the area of the triangle ABC.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

{Area}=\frac{1}{2} b c \sin A

where b=19, c=24 and m\angle A=65^{\circ}

Substituting these values in the above formula, we get,

{Area}=\frac{1}{2}(19)(24)  \sin 65^{\circ}

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Rounding off to the nearest tenth, we get,

{Area}=207.5

Thus, the area of the triangle ABC is 207.5 square units.

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3 years ago
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3 years ago
Y/3 - 4 = -1 solve for y
Marysya12 [62]

Answer:

y=9

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Carrie can inspect a case of watches in two hours. Jerry inspects a case in five hours. After inspecting a case for a half an ho
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Write the hours as ratio

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We need to work out the proportion of the time Jerry would take in comparison to 1.5 hours that Carrie would have taken.

First, we divide 2 by 1.5 ⇒ \frac{2}{1.5}= \frac{4}{3}

Then we divide 5 by 4/3 ⇒ \frac{5}{4/3} = \frac{5*3}{4} =3.75 hours

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3 years ago
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