A, b, c , d someone hurry up and answer

The probability that a randomly chosen person has a dog is 0.34. The probability that a randomly chosen person will have a dog a

Elina [12.6K]

Taking into definition of probability, the probability that a randomly chosen person is not walking in the park is 0.91.

<h3>Definition of Probabitity</h3>

Probability is the possibility that a phenomenon or an event will happen, given certain circumstances. It is expressed as a percentage.

<h3>Union of events</h3>

The union of events, AUB, is the event formed by all the elements of A and B. That is, the event AUB is verified when one of the two, A or B, or both occurs. AUB is read as "A or B".

The probability of the union of two compatible events is calculated as the sum of their probabilities subtracting the probability of their intersection:

P(A∪B)= P(A) + P(B) -P(A∩B)

<h3>Complementary event</h3>

A complementary event is made up of the inverse of the results of another event. That is, That is, given an event A, a complementary event is verified as long as the event A is not verified.

The probability of occurrence of the complementary event A' will be:

P(A´)= 1- P(A)

<h3>Events and probability in this case</h3>

In first place, let's define the following events:

D: a person has a dog.
W: a person is walking in the park.

Then you know:

P(D)= 0.34
P(D and W)= P(D∩W)= 0.03 [The intersection of events, A ∩ B, is the event formed by all the elements that are, at the same time, from A and B. That is, the event A ∩ B is verified when A and B occur simultaneously.]
P(D or W)= P(D∪W)= 0.40

In this case, considering the definition of union of eventes, the probability that a randomly chosen person is walking in the park is calculated as:

P(D∪W)= P(D) + P(W) -P(D∩W)

0.40= 0.34 + P(W) -0.03

Solving:

0.40= 0.31 + P(W)

0.40 - 0.31= P(W)

Then, the probability that a randomly chosen person is walking in the park is 0.09.

Considering the definition of the complementary event and its probability, the probability that a randomly chosen person is NOT walking in the park is calculated as:

P [W']= 1- P(W)

Replacing and solving:

P [W']= 1 - 0.09

P [W']= 0.91

Finally, the probability that a randomly chosen person is not walking in the park is 0.91.

Learn more about probability:

brainly.com/question/25839839

brainly.com/question/26038361

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7 0

2 years ago

Need this by midnight please show your work :)

Marina CMI [18]

Answer:

See below

Step-by-step explanation:

P = $800
r = 2% (since P > $500)
I = $100
t = ?

I = Prt

100 = 800*0.02t
0.16t = 1
t = 1/0.16
t = 6.25 years

P = $100
r = 1.5% (since P < $500)
I = $50
t = ?

I = Prt

50 = 100*0.015t
0.03t = 1
t = 1/0.03
t = 33.33 years

P = $10000
r = 3% (since P > $5000)
I = $750
t = ?

I = Prt

750 = 10000*0.03t
300t = 750
t = 750/300
t = 2.5 years

4 0

2 years ago

The table displays data for Nutrition Guides of a single serving of particular foods. Assuming there exists a correlation betwee

xz_007 [3.2K]

Answer:

The linear regression model that will determine approximate Fat Grams (y) as a function of Calories (x) is given by

y = 0.054 x - 2.105

Hence the correct option is B.)

Step-by-step explanation:

Step 1: Find X⋅Y and as it was done in the table below.

Step 2: Find the sum of every column:

ΣX = 1560, ΣY = 67, ΣX.Y = 14860 , ∑( $\textbf{X}^{2}$ ) = 337600

Step 3: Use the following equations to find a and b:

a = = -2.105

b = $\frac{n.\sum{XY} - \sum{X}.\sum{Y}}{n.\sum{(X^{2})}- (\sum{X})^{2} }$ = 0.054

Step 4: Substitute a and b in regression equation formula

y = a + b⋅x= −2.105 + 0.054⋅x

The linear regression model that will determine approximate Fat Grams (y) as a function of Calories (x) is given by

y = 0.054 x - 2.105

Hence the correct option is B.)

7 0

3 years ago

2. Kimora has 2 peaches, 1 apple, and 3

mestny [16]

Answer:

3/5

Step-by-step explanation:

There are 2 peaches + 1 apple + 3 oranges in the basket. There are a total of 5 fruits in the basket and 3 of them are oranges. If you randomly pick one the chances of you getting an orange if 3 out of 5.

8 0

3 years ago

Read 2 more answers

Cannnn u helpp me ill be choosing brainliest

allochka39001 [22]

$1) y=-5^{-x}, y = x+5 ,
\\ \\ -5^{-x}=x+5
\\ \\ ln(-5^{-x})=ln(x+5)
\\ \\ ln(- \frac{1}{5^{x}} )=ln(x+5),

you cannot find ln of negative number, so it is going to be

 "0" solutions.
$

The graphs of these equations will not intersect.

$2) y = 4(1.2)^{x}, y = x+7
\\ \\ x+7= 4(1.2)^{x}

graphs have 2 intersects, so two solutions.$

3) $y= {0.5}^{x} , y =6, \ 6=0.5^{x}

One intercept. so one solution$

3 0

4 years ago