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Burka [1]
3 years ago
15

Plz help! Math problem!

Mathematics
1 answer:
VMariaS [17]3 years ago
5 0
Remember
(ab)/(cd)=(a/c)(b/d)
basically you can move around them
also
\frac{x^m}{x^n} =x^{m-n}
so
remember that the first number hast to be greater than 1 and less than 10
\frac{8.82*10^5}{9*10^2}= ( \frac{8.82}{9} )( \frac{10^5}{10^2} )=
(0.98)(10^3)=(0.98)(10^1)(10^2)=9.8*10^2
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