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Taya2010 [7]
3 years ago
6

James surveyed people at school and asked whether they bring their lunch to school or buy their lunch at school more often. The

results are shown below.
Bring lunch: 46 males, 254 females
Buy lunch: 176 males, 264 females
The events "male” and "buys lunch” are not independent because
P(buys lunch | male) = P(male) = 0.4.
P(male | buys lunch) = P(male) = 0.3.
P(buys lunch | male) = 0.3 and P(male) = 0.4.
P(male | buys lunch) = 0.4 and P(male) = 0.3.
Mathematics
2 answers:
den301095 [7]3 years ago
6 0

Answer:

D. P(male | buys lunch) = 0.4 and P(male) = 0.3.

Step-by-step explanation:

tamaranim1 [39]3 years ago
3 0
46 + 176 = 222 males
254 + 364 = 518

Which is  total of 740 people.

The probability of being male is 0.3

46 + 254 = 300 that bring lunch
176 + 264 = 440 that buy their lunch 
P(male | buy lunch ) = 0.4

Answer D 
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A movie theater has been charging $10.00 per person and selling about 500 tickets on a typical weeknight. After surveying their
kifflom [539]

Answer:

p(x) = -0.01x + 15

Step-by-step explanation:

Given

Let x represent the number of tickets, and p the charges

(x_1,p_1) = (500,10)

A reduction of 50c gives an increment of 50 tickets.

This gives:

(x_2,p_2) = (500+50,10-0,5) ---- 50c = \$0.5

(x_2,p_2) = (550,9.5)

Required

Determine the demand function

First, calculate the slope:

m = \frac{p_2 - p_1}{x_2 - x_1}

m = \frac{9.5 - 10}{550-500}

m = \frac{-0.5}{50}

m = -0.01

So, the equation is:

p = m(x - x_1) + y_1

p = -0.01(x - 500) +10

p = -0.01x + 5 +10

p = -0.01x + 15

Hence, the function is:

p(x) = -0.01x + 15

4 0
3 years ago
150=2x do the work out please​
IrinaVladis [17]

Answer:

Let's solve the expression!

Step-by-step explanation:

150 = 2x

\frac{150}{2}=\frac{2x}{2}

75 = x

Your answer is 75.

The fraction shows 150 ÷ 2 and 2x ÷ 2.

I hope this helps!

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
7 0
2 years ago
Read 2 more answers
Find the point(s) on the surface z^2 = xy 1 which are closest to the point (7, 11, 0)
leonid [27]
Let P=(x,y,z) be an arbitrary point on the surface. The distance between P and the given point (7,11,0) is given by the function

d(x,y,z)=\sqrt{(x-7)^2+(y-11)^2+z^2}

Note that f(x) and f(x)^2 attain their extrema, if they have any, at the same values of x. This allows us to consider the modified distance function,

d^*(x,y,z)=(x-7)^2+(y-11)^2+z^2

So now you're minimizing d^*(x,y,z) subject to the constraint z^2=xy. This is a perfect candidate for applying the method of Lagrange multipliers.

The Lagrangian in this case would be

\mathcal L(x,y,z,\lambda)=d^*(x,y,z)+\lambda(z^2-xy)

which has partial derivatives

\begin{cases}\dfrac{\mathrm d\mathcal L}{\mathrm dx}=2(x-7)-\lambda y\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dy}=2(y-11)-\lambda x\\\\\dfrac{\mathrm d\mathcal L}{\mathrm dz}=2z+2\lambda z\\\\\dfrac{\mathrm d\mathcal L}{\mathrm d\lambda}=z^2-xy\end{cases}

Setting all four equation equal to 0, you find from the third equation that either z=0 or \lambda=-1. In the first case, you arrive at a possible critical point of (0,0,0). In the second, plugging \lambda=-1 into the first two equations gives

\begin{cases}2(x-7)+y=0\\2(y-11)+x=0\end{cases}\implies\begin{cases}2x+y=14\\x+2y=22\end{cases}\implies x=2,y=10

and plugging these into the last equation gives

z^2=20\implies z=\pm\sqrt{20}=\pm2\sqrt5

So you have three potential points to check: (0,0,0), (2,10,2\sqrt5), and (2,10,-2\sqrt5). Evaluating either distance function (I use d^*), you find that

d^*(0,0,0)=170
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d^*(2,10,-2\sqrt5)=46

So the two points on the surface z^2=xy closest to the point (7,11,0) are (2,10,\pm2\sqrt5).
5 0
3 years ago
If one of the factors of r ^ 2 + 21r + 98 is r + 7 , what is the other factor?
irina [24]

Answer:

i think factor the expression (r+7)(r+14) is answer

Step-by-step explanation:

8 0
2 years ago
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What is the product of 1 2/3 and −3 1/2?
Fynjy0 [20]
<span>1 2/3 x  −3 1/2
= 5/3 x -7/2
= - 35/6
= - 5 5/6

answer
A. </span><span>−5 5/6 ​</span>
6 0
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