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3 years ago

Help pls.. Fake answers will reported!...

Mathematics

1 answer:

ddd [48]3 years ago

4 0

Answer:

What ever q is divide it into fifths and then subtract whatever 1/5 of q equals from 8 and that'll be your answer.

Step-by-step explanation:

You might be interested in

Complete the table above.

4vir4ik [10]

$\bf \begin{array}{|c|c|c|ll}
\cline{1-3}
x&y=3x^2&y=3^x\\
\cline{1-3}&&\\
0&\stackrel{3(0)^2}{0}&\stackrel{3^0}{1}\\&&\\
1&\stackrel{3(1)^2}{3}&\stackrel{3^1}{3}\\&&\\
2&\stackrel{3(2)^2}{12}&\stackrel{3^2}{9}\\&&\\
\cline{1-3}
\end{array}$

4 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

I'm in algebra 1 please help i'm so lost

9966 [12]

3+xx=19

x2+3=19

x2+3−3=19

−3x2=16

x=±√16

x = 4‌‌ or ‌‌x = −4

6 0

3 years ago

Find the surface area of the rectangular prism

Mars2501 [29]

6 for the two bases = 12
6 x 2 = 12 for the 4 faces = 48
48+12 = 60 cm^2

7 0

2 years ago

Test the claim that the proportion of people who own cats is significantly different than 90% at the 0.1 significance level.

miss Akunina [59]

Answer:

The right answer is Option B:

$H_0: \pi=0.9\\\\H_1: \pi\neq0.9$

Step-by-step explanation:

In this case we have to perform a hypothesis test on the proportion of the people owning cats.

The claim is that the proportion is significantly different than 905, what means it can be greater or smaller than 90% to reject the null hypothesis. Because of that, the null hypothesis has to state an equality (H0:p=0.9).

The right answer is Option B:

$H_0: \pi=0.9\\\\H_1: \pi\neq0.9$

4 0

3 years ago