Answer:
you first start by making your equation: 45 +.25x = 70 +.15x. then subtract .15x from both sides. it should look like 45 +.10x = 70. subtract 45 from both sides then you get .10x = 25. divide 10 to both sides and you get 250. so the two companies will be the same at 250 texts.
Step-by-step explanation:
Answer:
$10,100 000,000.006 but it says round to the dollar so it is $10,100 000,000
Step-by-step explanation:
136/100 × $7,426,470,588.24
Step-by-step explanation:
In statistics, the empirical rule states that for a normally distributed random variable,
- 68.27% of the data lies within one standard deviation of the mean.
- 95.45% of the data lies within two standard deviations of the mean.
- 99.73% of the data lies within three standard deviations of the mean.
In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

where the symbol
(the uppercase greek alphabet phi) is the cumulative density function of the normal distribution,
is the mean and
is the standard deviation of the normal distribution defined as
.
According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution
,

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.
Tools for surgery and patching the person up where their wounds are
Answer:
The answer is below⬇️⬇️
Step-by-step explanation:
f(x) = 3x+4
g(x) = 2x
h(x) = x²+x-2
g(hx) = 2(x²+x-2)
= 2x²+2x-4
f(g(hx))=3(2x²+2x-4)+4
=6x²+6x-12+4
=6x²+6x-8
g(f(g(hx)))=2(6x²+6x-8)
=12x²+12x-16
f(g(f(g(hx))))=3(12x²+12x-16)+4
=36x²+36x-48+4
=36x²+36x-44
h(f(g(f(g(hx)))))=(36x²+36x-44)²+36x²+36x-44-2
=1296x⁴+2592x³-1872x²-3168x+1936+36x²+36x-46
=1296x⁴+2592x³-1836x²-3132x+1890
f(h(f(g(f(g(hx))))))=3(1296x⁴+2592x³-1836x²-3132x+1890)+4
=3888x⁴+7776x³-5508x²-9396x+5674
h(f(h(f(g(f(g(hx)))))))=(3888x⁴+7776x³-5508x²-9396x+5674)²+3888x⁴+7776x³-5508x²-9396x+5674-2
=15116544x⁸+60466176x⁷+17635968x⁶-158723712x⁵-71663616x⁴+657591048x³-255531048x²-106635204x+32194276