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Bess [88]
3 years ago
5

There are 6 2/3 pounds of walnuts in a container, which will be divided equally into containers that hold 1 1/2pounds. This woul

d fill and 4/9 containers. (3 points)
Mathematics
1 answer:
9966 [12]3 years ago
6 0

Step-by-step explanation:

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A survey of 73 students found that 37% were in favor of raising tuition to pave new parking lots. The standard deviation of the
KatRina [158]

Answer:

The value  is   n_2  = 317

Step-by-step explanation:

From the question we are told that

  The sample size is  n  =  73

   The proportion that in favor of raising the tuition is  \^{p} =  0.37

   The standard deviation is  s_1  = 0.098

    The required standard deviation  s_2  = 0.047

Generally the requires standard deviation is mathematically represented as

      s_2  = s_1 *  \sqrt{\frac{n_1}{n_2} }

=>    \frac{s_2}{s_1}  =  \sqrt{\frac{n_1}{n_2} }

=>    \frac{n_1}{n_2} =[\frac{s_2}{s_1} ]^2

=>     \frac{73}{n_2} =[\frac{0.047}{0.098} ]^2

=>     \frac{73}{n_2} =0.2300

=>     n_2 =  \frac{73}{0.2300}

=>   n_2  = 317

3 0
3 years ago
a plane flies 5.0km due north from a point O and then 6.0km on a bearing of 060° the pilot then changes course on a bearing of 1
Virty [35]

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

A plane that travels a distance r, in kilometers, with a bearing of \theta sexagesimal degrees can be represented in standard position by means of the following expression:

\vec r = r\cdot (\sin\theta, \cos \theta) (1)

We can obtain the resulting vector (\vec R) by the principle of superposition:

\vec R = \Sigma_{i=1}^{n} [r_{i}\cdot (\sin \theta_{i}, \cos \theta_{i})] (2)

If we know that r_{1} = 5\,km, \theta_{1} = 0^{\circ}, r_{2} = 6\,km, \theta_{2} = 60^{\circ}, r_{3} = 4\,km and \theta_{3} = 120^{\circ}, then the resulting vector is:

\vec R = 5\cdot (\sin 0^{\circ}, \cos 0^{\circ}) + 6\cdot (\sin 60^{\circ}, \cos 60^{\circ}) + 4\cdot (\sin 120^{\circ}, \cos 120^{\circ})

\vec R = (5\sqrt{3}, 6) \,[km]

The magnitude of the resultant is found by Pythagorean theorem:

\|\vec R\| = \sqrt{R_{x}^{2}+R_{y}^{2}}

And the bearing is determined by the following <em>inverse</em> trigonometric relationship:

\theta_{R} = \tan^{-1} \left(\frac{R_{y}}{R_{x}}\right) (3)

If we know that R_{x} = 5\sqrt{3}\,km and R_{y} = 6\,km, then the magnitude and the bearing of the resultant is:

\|\vec R\| = \sqrt{(5\sqrt{3})^{2}+6^{2}}

\|\vec R\| \approx 10.536\,km

\theta_{R} = \tan^{-1} \left(\frac{6}{5\sqrt{3}} \right)

\theta_{R} \approx 34.715^{\circ}

The plane flies a distance of approximately 10.536 kilometers in <em>straight</em> line and with a bearing of approximately 035°.

To learn more on vectors, we kindly invite to check this verified question: brainly.com/question/21925479

6 0
3 years ago
The community center has a pottery class each month. Each student pays $15 for the class and $27 for materials. This month the p
user100 [1]
15x+27x=714
42x=714
X=17
5 0
3 years ago
How to prove all pairs of corresponding sides and angles are congruent
Lera25 [3.4K]
The lines on the triangles
5 0
3 years ago
Length = 25cm, bredth =60 cm, Volume = 7500cm^3. Find height of a cuboid.
elena-14-01-66 [18.8K]

Answer:

height = 5cm

Step-by-step explanation:

Volume of the cuboid = length x breadth x height

7500 = 25 x 60 x height

height = 7500 / 1500

height = 5

8 0
3 years ago
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