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satela [25.4K]
3 years ago
6

A calculus exam that was taken by 94 students is recorded and normally distributed. The mean score on the exam is 78 and the sta

ndard deviation is 2.4. What percent of the scores are in the 70.8 and 85.2 range?
Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

99.73%

Step-by-step explanation:

If you have a calculator with distribution functions, this problem boils down to using a single command:

norm(70.8, 85.2, 78, 2.4) = 0.9973

This tells us that 99.73% of the scores are in the 70.8-85.2 range.

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Solve x - 6x = 40 by factoring. What is<br> the solution?
marta [7]

Answer:

x=-8

Step-by-step explanation:

collect like terms

-5x=40

divide both sides of the equation by -5

so the answer would be x=-8

7 0
3 years ago
A car rental company charges $34 per day for a rented car and $0.50 for every mile driven. A second car rental company charges $
Ludmilka [50]

Answer:

B 2/3

Step-by-step explanation:

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3 years ago
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Find a ratio equivalent to 15/60
Flauer [41]

Answer:

\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}

or

\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots

or

Multiply the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots

7 0
3 years ago
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The number of students in an school building that have the flu after t days is given by the function
gulaghasi [49]

Step-by-step explanation:

p(0) =  \frac{800}{1 + 49 {e}^{ - 0.2 \times 0} }  =  \frac{800}{1 + 49}  =  \frac{800}{50}  = 16

200 =  \frac{800}{1 + 49 {e}^{ - 0.2t} }  \\ 200(1 + 49 {e}^{ - 0.2t} ) = 800 \\ 200 + 9800 {e}^{ - 0.2t}  = 800 \\ 9800 {e}^{ - 0.2t}  = 600 \\  {e}^{ - 0.2t}  =  \frac{3}{49}  \\  ln( {e}^{ - 0.2t} )  =  ln( \frac{3}{49} )  \\ -  0.2t =  - 2.793 \\ t = 13.96 = 14

6 0
3 years ago
21 ten thousands + 18 ones + 60 hundreds
Vinvika [58]
21,618.........................
3 0
3 years ago
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