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Alinara [238K]
3 years ago
11

If the fraction 396\x-10 is equivalent to -22. find the value of x.

Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0
396/x - 10 = -22 396/x = -22 + 10 396/x = -12 X = -396/12 X = -33
____ [38]3 years ago
3 0

Answer:

The value of x is -33.

Step-by-step explanation:

Consider the provided information.

The fraction 396\x-10 is equivalent to -22.

This can be written as:

\frac{396}{x}-10=-22

Add 10 to the both the sides.

\frac{396}{x}-10+10=-22+10

\frac{396}{x}=-12

Multiply both the sides by x.

396=-12x

Now divide both the sides by -12.

\frac{396}{-12}=x

x=-33

Hence, the value of x is -33.

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Abelita and Franco spent $11.74 on food. The sales tax for 5 percent is $56 cents. 

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In the diagram below of triangle GHIGHI, JJ is the midpoint of \overline{GI} GI and KK is the midpoint of \overline{HI} HI . If
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Answer:

25.5

Step-by-step explanation:

2( -21+9x)=2x+18

-42+18x=2x+18

+42            +42

18x=2x+60

-2x -2x

16x=60

60/16=3.75

x=3.75

GH=2x+18

2(3.75)+18

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4 0
3 years ago
On which of the following lines does the point (7, 1) lie?
stealth61 [152]
We have that
<span>the point (7, 1)

case </span><span>A.) y = 5x + 4
if the point </span>(7, 1) lie to the line
so
for x=7 the value of y must be  1
y=5*7+4------> y=39
39 is not 1---------> the point does not belong to the line

case <span>B.) y = -x + 8
</span>if the point (7, 1) lie to the line
so 
for x=7 the value of y must be  1
y=-7+8------> y=1--------> the point belongs to the line

case <span>C.) y = x - 10
</span>if the point (7, 1) lie to the line
so 
for x=7 the value of y must be  1
y=7-10------> y=-3
-3 is not 1---------> the point does not belong to the line

case <span>D.) y = -4x + 3
</span>if the point (7, 1) lie to the line
so 
for x=7 the value of y must be  1
y=-4*7+3------> y=-25
-25 is not 1---------> the point does not belong to the line

the answer is the option
 B.) y = -x + 8
6 0
3 years ago
I need to use Multi-Step function inverse to find the following:
dexar [7]

<u>Answer</u>:

f^{-1}(x) = \sqrt[5]{\frac{x+7}{9} -10}

<u>Explanation</u>:

given : f(x) = 9( x^5 + 10 ) - 7

replace x and y with each other.

  • x = 9( y^5 + 10 ) - 7

solve for y

  • x + 7 = 9( y^5 + 10 )
  • ( y^5 + 10 ) = \frac{x + 7}{9}
  • y^5 + 10 = \frac{x + 7}{9}
  • y^5 = \frac{x + 7}{9} - 10
  • y = \sqrt[5]{\frac{x+7}{9} -10}

Therefore,

  • f^{-1}(x) = \sqrt[5]{\frac{x+7}{9} -10}
5 0
2 years ago
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