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Anna71 [15]
3 years ago
14

Rectangles ABCD and EFGH are similar. The perimeter of rectangle ABCD is 5 times greater than the perimeter of rectangle EFGH. W

hat is the relationship between the areas of the rectangles?
A. The area of rectangle EFGH is 25 times greater than the area of rectangle ABCD.
B. The area of rectangle EFGH is 5 times greater than the area of rectangle ABCD.
C. The area of rectangle ABCD is 25 times greater than the area of rectangle EFGH.
D. The area of rectangle ABCD is 5 times greater than the area of rectangle EFGH.
Mathematics
2 answers:
yulyashka [42]3 years ago
7 0
C.  Area of rectangle is A=L X W

If the length is 5 times bigger and the width is 5 times bigger, than the area is 25 times bigger
Vesnalui [34]3 years ago
6 0

Answer:

Step-by-step explanation:

Thank you

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4 0
3 years ago
A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.
blsea [12.9K]

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}

Simplifying, we get;

A=\frac{64 \times 10}{4 (\tan \ 18)}

A=\frac{640}{4 (0.325)}

A=\frac{640}{1.3}

A=642.3

Rounding off to the nearest whole number, we get;

A=642 \ cm^2

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

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Averi was trying to factor 4x^2+20x-164x
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Answer:

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Step-by-step explanation:

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