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Anna71 [15]
3 years ago
14

Rectangles ABCD and EFGH are similar. The perimeter of rectangle ABCD is 5 times greater than the perimeter of rectangle EFGH. W

hat is the relationship between the areas of the rectangles?
A. The area of rectangle EFGH is 25 times greater than the area of rectangle ABCD.
B. The area of rectangle EFGH is 5 times greater than the area of rectangle ABCD.
C. The area of rectangle ABCD is 25 times greater than the area of rectangle EFGH.
D. The area of rectangle ABCD is 5 times greater than the area of rectangle EFGH.
Mathematics
2 answers:
yulyashka [42]3 years ago
7 0
C.  Area of rectangle is A=L X W

If the length is 5 times bigger and the width is 5 times bigger, than the area is 25 times bigger
Vesnalui [34]3 years ago
6 0

Answer:

Step-by-step explanation:

Thank you

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Determine the zeros of r=2sin5theta
vazorg [7]

Answer:

\theta=\frac{n\pi}{5}

Step-by-step explanation:

You have the following function:

r=2sin5\theta          (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^{-1}(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=\frac{n\pi}{5}

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.

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3 years ago
Question is down below
mr Goodwill [35]
The correct answer would be B.
7 0
4 years ago
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luda_lava [24]
X = 11 because if you take 11 x 2 then you get 22 then add 5 to it then you got 27 or if you do it the algebraic way subtract 5 from 27 to get 2x = 22 then divide both sides by 2 to get x = 11

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Answer:

-16

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zimovet [89]
Use the equation

t = -b / (2a)

where:
a = -16
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b)

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